如何根据某个类计算图像的渐变?

Geo*_*Liu 8 numpy image deep-learning conv-neural-network tensorflow

ImageNet上Breaking Linear Classifiers中,作者提出了以下方法来创建欺骗ConvNets的对抗图像:

简而言之,为了创建一个愚蠢的图像,我们从我们想要的任何图像(实际图像,甚至是噪声模式)开始,然后使用反向传播来计算任何类别得分上的图像像素的渐变,并轻推它.我们可以,但不必,重复几次这个过程.您可以将此设置中的反向传播解释为使用动态编程来计算对输入的最具破坏性的局部扰动.请注意,如果您可以访问ConvNet的参数(backprop很快),此过程非常有效并且花费的时间可以忽略不计,但即使您无法访问参数但只能访问类别分数,也可以执行此操作在末尾.在这种情况下,可以用数字方式计算数据梯度,或者使用其他局部随机搜索策略等.注意,由于后一种方法,即使是非可微分类器(例如随机森林)也不安全(但我还没见过有人凭经验证实这一点.

我知道我可以像这样计算图像的渐变:

np.gradient(img)
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但是如何使用TensorFlow或Numpy计算图像相对于另一个图像类的渐变?可能我需要做一些类似于本教程中的过程的东西?如:

cross_entropy = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(y_conv, y_))
train_step = tf.train.AdamOptimizer(1e-4).minimize(cross_entropy)
correct_prediction = tf.equal(tf.argmax(y_conv,1), tf.argmax(y_,1))
accuracy = tf.reduce_mean(tf.cast(correct_prediction, tf.float32))
sess.run(tf.initialize_all_variables())
for i in range(20000):
  batch = mnist.train.next_batch(50)
  if i%100 == 0:
    train_accuracy = accuracy.eval(feed_dict={
        x:batch[0], y_: batch[1], keep_prob: 1.0})
    print("step %d, training accuracy %g"%(i, train_accuracy))
  train_step.run(feed_dict={x: batch[0], y_: batch[1], keep_prob: 0.5})

print("test accuracy %g"%accuracy.eval(feed_dict={
    x: mnist.test.images, y_: mnist.test.labels, keep_prob: 1.0}))
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但我不确定具体如何...具体来说,我有一个数字2的图像如下: 在此输入图像描述

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如何计算此图像相对于数字6图像类的梯度(下面显示的示例)?(我想我需要使用反向传播来计算所有数字6图像的渐变.) 在此输入图像描述

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Run Code Online (Sandbox Code Playgroud)

在此先感谢您的帮助!

以下是我提出的两个相关问题:

如何使用图像和权重矩阵在TensorFlow中创建对抗图像?

如何为ConvNet创建对抗图像?

这是我的剧本.

Kei*_*hWM 1

仅班级成绩

如果您只能访问任何图像的类别分数,您建议您没有太多花哨的方法来真正计算梯度。

如果返回的内容可以看作每个类别的相对分数,那么它就是一个向量,它是某个函数作用于包含图像*上所有信息的向量v的结果。函数的真实梯度由矩阵 给出,该矩阵取决于,使得在任何 的小极限内。您可以使用 epsilon 的一些小值和多个测试矩阵(每个元素一个就足够了)来对此进行数值近似,但这可能会不必要地昂贵。fAD(A)AD(A)*B = (f(A + epsilon*B) -f(A))/epsilonepsilonBBA

您要做的就是最大化算法识别图像的难度。也就是说,对于给定的算法,f您希望最大化一些适当的度量,以衡量算法识别每个图像的程度A。为此有很多方法。我对它们不太熟悉,但我最近看到的一次演讲对此有一些有趣的材料(https://wsc.project.cwi.nl/woudschoten-conferences/2016-woudschoten-conference/PRtalk1.pdf,请参阅页面24 及以后)。如果您有高维输入,计算整个梯度通常会太昂贵。相反,您只需修改随机选择的坐标,并或多或少地朝着正确的方向采取许多(许多)小而便宜的步骤,而不是寻求某种最佳的大但昂贵的步骤。

型号可用且适用

如果您完全了解模型并且可以明确地编写为,v = f(A)那么您可以计算函数的梯度f。如果您尝试击败的算法是线性回归(可能具有多层),就会出现这种情况。渐变的形式对你来说应该比我在这里写下来更容易理解。

有了这个梯度,并且评估其对于不同图像的值相当便宜A,您就可以继续使用例如最速下降(或上升)方法来使算法难以识别图像。

重要的提示

最好不要忘记,您的方法也不应该使图像对人类来说难以辨认,这将使一切变得毫无意义。

  • 我认为出于本次讨论的目的,最好将图像视为矢量