在python中使用swagger codegen客户端向api调用添加标头的细节尚不清楚

dla*_*lin 5 python swagger swagger-codegen

指出正确的文档,教程,示例或提供一个,显示如何将特定的身份验证令牌添加到Python中Swagger生成的API客户端中的特定标头?

这是我尝试过的:
使用正确的curl命令,我的API调用工作得很好:

curl -v -H 'X-CAG-Authorization: AG_CONSUMER_TOKEN access-key=31337-70k3n' \
     'https://api.company.net/api/v1/user/detail?user=1'

*   Trying 10.10.1.10...
* Connected to api.company.net (10.10.1.10) port 443 (#0)
* TLS 1.2 connection using TLS_ECDHE_RSA_WITH_AES_256_GCM_SHA384
* Server certificate: *.company.net
* Server certificate: COMODO RSA Organization Validation Secure Server CA
* Server certificate: COMODO RSA Certification Authority
> GET /api/v1/user/detail?user=1 HTTP/1.1
> Host: api.company.net
> User-Agent: curl/7.49.1
> Accept: */*
> X-CAG-Authorization: AG_CONSUMER_TOKEN access-key=31337-70k3n
> 
< HTTP/1.1 200 OK
< Server: openresty
< Date: Thu, 22 Dec 2016 19:46:05 GMT
< Content-Type: application/json;charset=UTF-8
< Transfer-Encoding: chunked
< Connection: close
< Vary: Accept-Encoding
< Vary: Accept-Encoding
< X-UA-Compatible: IE=edge
< 
{"successful":true,"message":"SUCCESS","body":{"…
Run Code Online (Sandbox Code Playgroud)

但是,当我在我的Python(2.7.12)客户端中尝试相同的基本请求时,我获得了授权失败,尽管确认该令牌使其成为即将使用的标头.有关正确使用客户端的方法或如何获取确切请求和响应的更多详细信息的更多详细信息将不胜感激.

/Users/me/VEnvs/sku-grade/bin/python /Users/me/prj/code/python_client/api_example.py
HEADERS:
{'X-CAG-Authorization': 'AG_CONSUMER_TOKEN access-key=31337-70k3n', 'User-Agent': 'Swagger-Codegen/1.0.0/python'}
Exception when calling SupplierApi->get_api_v1_user_details: (401)
Reason: Unauthorized
HTTP response headers: HTTPHeaderDict({'Date': 'Thu, 22 Dec 2016 21:09:30 GMT', 'Content-Length': '636', 'Content-Type': 'application/json; charset=UTF-8', 'Connection': 'keep-alive', 'Server': 'nginx'})
HTTP response body: {
  "code" : "PRECONDITION_FAILED",
  "type" : "UnauthorizedApiDeniedException",
  "message" : "Target API(/api/v1/user/details) is not available, you have to get a grant in advance.",
  "messages" : {…
Run Code Online (Sandbox Code Playgroud)

这是一个昂首阔步的api规范: swagger.yaml

---
swagger: "2.0"
info:
  description: "API"
  version: "TEMPORARY"
  title: "User Details"
  termsOfService: "http://wiki.company.net/tos"
  contact:
    name: "…"
  license:
    name: "…"
host: "api.company.net"
basePath: "/api/v1"
tags:
- name: "supplier"
  description: "Supplier"
schemes:
- "https"
produces:
- "application/json"
paths:
  /user/details:
    get:
      tags:
      - "supplier"
      summary: "userDetails"
      operationId: "getApiV1UserDetails"
      consumes:
      - "application/json"
      produces:
      - "application/json;charset=utf-8"
      parameters:
      - name: "user"
        in: "query"
        description: "user id"
        required: true
        type: "integer"
        format: "Long"
      responses:
        200:
          description: "OK"
          schema:
            $ref: "#/definitions/SupplierResponseOfUserDetailsDto"
        401:
          description: "Unauthorized"
        403:
          description: "Forbidden"
        404:
          description: "Not Found"
definitions:
  SupplierResponseOfUserDetailsDto:
    type: "object"
    properties:
      body:
        $ref: "#/definitions/UserDetailsDto"
      message:
        type: "string"
      successful:
        type: "boolean"
  UserDetailsDto:
    type: "object"
    properties:
      name:
        type: "string"
Run Code Online (Sandbox Code Playgroud)

swagger-codegen是从http://editor.swagger.io/运行的,我按照api示例尝试添加额外的标头:api_example.py

from __future__ import print_function
import time
import swagger_client
from swagger_client import ApiClient
from swagger_client import Configuration
from swagger_client.rest import ApiException
from pprint import pprint

# Setup the authentication token header
conf = Configuration()
conf.api_key_prefix = {"teamname": "AG_CONSUMER_TOKEN"}
conf.api_key = {
    "teamname": "access-key=31337-70k3n"
}
conf.api_client = ApiClient(None, "X-CAG-Authorization",
                            conf.get_api_key_with_prefix("teamname"))

# create an instance of the API class
api_instance = swagger_client.SupplierApi()
user = 1
try:
    api_response = api_instance.get_api_v1_user_details(user)
    pprint(api_response)
except ApiException as e:
    print("Exception when calling "
          "SupplierApi->get_api_v1_user_details: %s\n" % e)
Run Code Online (Sandbox Code Playgroud)

通过将一个print(self.api_client.default_headers)supplier_api.py我可以看到的是,头也似乎被设定.

{'X-CAG-Authorization': 'AG_CONSUMER_TOKEN access-key=31337-70k3n', 'User-Agent': 'Swagger-Codegen/1.0.0/python'}
Run Code Online (Sandbox Code Playgroud)

那么我的例子又应该改变一下,让它传递标题并获得完全符合简单卷曲调用的方式?

更新我也试过定义它:

      security:
      - api_key: []
securityDefinitions:
  api_key:
    type: "apiKey"
    name: "X-CAG-Authorization"
    in: "header"
Run Code Online (Sandbox Code Playgroud)

然后只设置密钥:

swagger_client.configuration.api_key['X-CAG-Authorization'] = \
    'access-key=31337-70k3n'
swagger_client.configuration.api_key_prefix['X-CAG-Authorization'] = \
    'AG_CONSUMER_TOKEN'
Run Code Online (Sandbox Code Playgroud)

但是除了标题从我正在打印的默认标题中消失之外,这并没有太大变化.

pre*_*per 3

我已经尝试过您的代码示例,看起来您的标头实际上已传递到服务器。

您可以通过在此之前添加print headers到文件来确认这一点:swagger_client/rest.py

r = self.pool_manager.request(method, url,
                              fields=query_params,
                              preload_content=_preload_content,
                              timeout=timeout,
                              headers=headers)
Run Code Online (Sandbox Code Playgroud)

确定服务器端没有问题吗?也许某些标头破坏了身份验证?

下面的curl命令也可以工作吗?

curl -v \
 -H 'X-CAG-Authorization: AG_CONSUMER_TOKEN access-key=31337-70k3n' \
 -H 'Content-Type: application/json' \
 -H 'Accept: application/json;charset=utf-8' \
 -H 'User-Agent: Swagger-Codegen/1.0.0/python' \
 'https://api.company.net/api/v1/user/detail?user=1'
Run Code Online (Sandbox Code Playgroud)

因为这应该给你返回与 swagger 完全相同的答案,即 401 错误。如果是这样,您可以从服务器端进行调试。如果没有,我就不知道了。