一个javascript摇滚,纸,剪刀游戏!

Question

嘿伙计们,我正在制作一个javascript摇滚,纸张,剪刀游戏!所以代码在下面,它不起作用警报没有显示,我真的不知道我搞砸了.

function randomNumber(x,y){                 //returns a random number from an interval given
    var z;
    if (x>y) {z=x; x=y; y=z;}               // turns the interval upside down if the numbers of the interval are entered in unconsecutive order
    else if(x==y) {return x; break;}        //if there's no interval but two same digits return the number entered
    var randomNo = (y-x)*Math.random() + x; // the random value itself in float type
    Math.round(randomNo);                   // round it to integer
}

function outcomeType(value){                    //gives the type of hand-symbol in game for each player according to the random No given
    var outcome;
    if (value==1 || value==4){outcome="rock"}   //value 1 or 4 gives rock, same way with other two...
    else if(value==2) {outcome="paper"}
    else {outcome="scissors"}
    return outcome; 
}

function result(x,y){          // compares the numbers so that a winner is decided
    if(x>y){return 1}         //player A wins
    else if(x==y){return 0;} //draw
    else {return 2}         //player B wins
}

function game(){
    var a=randomNumber(1,3); // random number for player A
    var b=randomNumber(1,3);// random number for player B

    if(a!=2 && b!=2 && a!=b){ //the case rock-scissors, rocks from 1 beecomes 4 in order to beat in result()
        if(a>b){b=4}
        else{a=4}
    }

    var winner = result(a,b); // we have a winner!!!
    if (winner==1) {alert("Player A wins with"+outcomeType(a)+"against"+outcomeType(b););} // the alert should be like: Player A wins with "scissors" against "paper"
    else if (winner==0) {alert("Draw with"+outcomeType(a););}                               //draw
    else {alert("Player B wins with"+outcomeType(b)+"against"+outcomeType(a););}            //player B winning alet

}

感谢任何帮助

Answer 1

我认为给你自己回答这个问题的工具更重要,而不是发布一些有效的代码.你目前如何使用javascript？

我强烈建议使用firefox + firebug,学会使用它,你就可以在几分钟内自行修复.

它指出代码中的所有3个语法错误,然后运行,但总是返回相同的值.在游戏功能中添加断点并快速逐步显示随机功能被破坏,并且没有返回.

Answer 2

一个相当严重的问题是你的"randomNumber"例程实际上return没有任何东西.最后一行应该(可能)

return Math.round(randomNo);                   // round it to integer