如何单独提交附加表格

Question

标有NEWFORM的按钮可在单击时创建新表单.每个表单都有一个提交按钮.单击每个表单的提交按钮时,该表单的值将通过AJAX发送.我的代码第一次运行良好,但是当创建并提交新表单时,所有表单的所有值都将一起发送.

这是我的片段:

$(document).ready(function() {
  $(".newform").click(function() {
    $(".MyForm")
    .eq(0)
    .clone()
    .show()
    .insertAfter(".MyForm:last");
  });

  $(document).on('click', '.MyForm button[type=submit]', function(e) {
    e.preventDefault() // To make sure the form is not submitted 
    $('.MyForm').each(function() {
     console.log($(this).serialize())
      $.ajax(
        $(this).attr('action'), 
        {
          method: $(this).attr('method'),
          data: $(this).serialize()
        }
      )
    });
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.1/jquery.min.js"></script>
<span class="newform">NEWFORM+</span>
<div class="all">
  <form class="MyForm" method="post">
    <input type="text" placeholder="name" value="Aynaz" name="a1" />
    <select name="Avg">
      <option value="1">1</option>
      <option value="2">2</option>
    </select>
    <button type="submit">Submit</button>
  </form>
</div>

Answer 1

您迭代解决方案中的所有“.MyForm”对象，因此所有这些对象都已提交，您需要首先在 onClick 中确定正确的表单，然后提交：

$(document).ready(function() {
  $(".newform").click(function() {
    $(".MyForm")
    .eq(0)
    .clone()
    .show()
    .insertAfter(".MyForm:last");
  });

  $(document).on('click', '.MyForm button[type=submit]', function(e) {
    e.preventDefault() // To make sure the form is not submitted 
    var $frm = $(this).closest('.MyForm');
    console.log($frm.serialize());
    $.ajax(
        $frm.attr('action'), 
        {
          method: $frm.attr('method'),
          data: $frm.serialize()
        }
    );
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.1/jquery.min.js"></script>
<span class="newform">NEWFORM+</span>
<div class="all">
  <form class="MyForm" method="post">
    <input type="text" placeholder="name" value="Aynaz" name="a1" />
    <select name="Avg">
      <option value="1">1</option>
      <option value="2">2</option>
    </select>
    <button type="submit">Submit</button>
  </form>
</div>