我在我的IDE中得到以下错误,说明Property id does not exist on type string typeScript
这行代码:
if(customer.id === id) {//doesn't like customer.id
return customer;
}
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完整代码:
let customer:any [];
function Customers(): string[] {
let id = 0;
createCustomer("Drew",id++,22,"Glassboro");
createCustomer("Mike",id++,40,"Rineyville");
createCustomer("Justin",id++,19,"Jonesboro");
createCustomer("Alex",id++,15,"Paulsboro");
createCustomer("Phil",id++,32,"Glassboro");
return customer;
}
function createCustomer(name:string,id:number,age:number,city:string){
customer.push(name,id,age,city);
}
const allCustomers = Customers();
function getCustomerInformation(id:number): string {
for (let customer of allCustomers) {
if(customer.id === id){
return customer;
}
}
return "";
}
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这是我的假设,因为我习惯了any
,let customer:any [];
我可以在那里放置不同的变量.
-----------------感谢您的帮助,这是我的新解决方案--------
interface ICustomer{
id: number;
name: string;
age: number
city: string
}
let customers: Array<ICustomer>;
function generateCustomers(): void {
let id: number = 0;
createCustomer("Drew", id++, 22, "Glassboro");
createCustomer("Mike", id++, 40, "Rineyville");
createCustomer("Justin", id++, 19, "Jonesboro");
createCustomer("Alex", id++, 15, "Paulsboro");
createCustomer("Phil", id++, 32, "Glassboro");
}
function getAllCustomers(): ICustomer[]{
generateCustomers();
return customers;
}
function createCustomer(name:string,id:number,age:number,city:string): void {
let newCustomer:ICustomer = {id:id,name:name,age:age,city:city};
customers.push(newCustomer);
}
const allCustomers = getAllCustomers;
function getCustomerInformation(id:number): ICustomer {
for (let customer of allCustomers()) {
if(customer.id === id){
return customer;
}
}
return null;
}
console.log(getCustomerInformation(1));
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Pio*_*ski 11
您必须将您的属性包装在对象内:
function createCustomer(name: string, id: number, age: number, city: string) {
customer.push({ name, id, age, city });
}
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{ name, id, age, city }
ES2015 在哪里等效:
{
id: id,
name: name,
age: age,
city: city
}
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为了避免这种错误,我倾向于创建强制结构的界面:
interface ICustomer {
id: number;
name: string;
age: number;
city: string;
}
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您分配给您的数组:
let customer: ICustomer[];
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除了更好的类型检查,它为您提供更好的语法提示.
编辑:我已经审核了您的代码并提供了一些有关实践的建议:
代码价值超过1000字.这是重构版本:
const allCustomers: ICustomer[] = customers();
interface ICustomer {
id: number;
name: string;
age: number;
city: string;
}
function customers(): ICustomer[] {
let id: number = 0;
return [
createCustomer(id++, "Drew", 22, "Glassboro"),
createCustomer(id++, "Mike", 40, "Rineyville"),
createCustomer(id++, "Justin", 19, "Jonesboro"),
createCustomer(id++, "Alex", 15, "Paulsboro"),
createCustomer(id++, "Phil", 32, "Glassboro")
];
}
function createCustomer(id: number, name: string, age: number, city: string): ICustomer {
return { id, name, age, city };
}
function getCustomerInformation(customers: ICustomer[], id: number): ICustomer {
// Note undefined is returned if object not found
return customers.find(customer => customer.id === id);
}
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