你如何修复以下Django错误:"类型:IOError""值:[Errno 13]权限被拒绝"

Stu*_*Stu 3 python django django-models django-settings

我正在关注Django教程,一旦图像保存在admin中,您需要构建一些图像缩略图.我也使用Python的tempfile模块来保存临时文件名.

但是我一直遇到以下错误:

"Type: IOError" "Value: [Errno 13] Permission denied: 'c:\\docume~1\\myname\\locals~1\\temp\\somefilename'"
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这是我正在使用的代码

设置

MEDIA_ROOT = '/home/myname/projectname/media/'
MEDIA_URL = 'http://127.0.0.1:8000/media/'enter code here
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models.py

from string import join
import os
from PIL import Image as PImage
from settings import MEDIA_ROOT
from os.path import join as pjoin
from tempfile import *
from string import join
from django.db import models
from django.contrib.auth.models import User
from django.contrib import admin
from django.core.files import File

class Image(models.Model):
    title = models.CharField(max_length=60, blank=True, null=True)
    image = models.FileField(upload_to="images/")
    thumbnail = models.ImageField(upload_to="images/", blank=True, null=True)
    tags = models.ManyToManyField(Tag, blank=True)
    albums = models.ManyToManyField(Album, blank=True)
    created = models.DateTimeField(auto_now_add=True)
    rating = models.IntegerField(default=50)
    width = models.IntegerField(blank=True, null=True)
    height = models.IntegerField(blank=True, null=True)
    user = models.ForeignKey(User, null=True, blank=True)
    thumbnail2 = models.ImageField(upload_to="images/", blank=True, null=True)

def save(self, *args, **kwargs):
    #Save image dimensions
    super(Image, self).save(*args, **kwargs)
    im = PImage.open(pjoin(MEDIA_ROOT, self.image.name))
    self.width, self.height = im.size

    # large thumbnail
    fn, ext = os.path.splitext(self.image.name)
    im.thumbnail((128,128), PImage.ANTIALIAS)
    thumb_fn = fn + "-thumb2" + ext
    tf2 = NamedTemporaryFile()
    im.save(tf2.name, "JPEG")
    self.thumbnail2.save(thumb_fn, File(open(tf2.name)), save=False)
    tf2.close()

    # small thumbnail
    im.thumbnail((40,40), PImage.ANTIALIAS)
    thumb_fn = fn + "-thumb" + ext
    tf = NamedTemporaryFile()
    im.save(tf.name, "JPEG")
    self.thumbnail.save(thumb_fn, File(open(tf.name)), save=False)
    tf.close()

    super(Image, self).save(*args, **kwargs)

def size(self):
    """Image size."""
    return "%s x %s" % (self.width, self.height)

def __unicode__(self):
    return self.image.name

def tags_(self):
    lst = [x[1] for x in self.tags.values_list()]
    return str(join(lst, ', '))

def albums_(self):
    lst = [x[1] for x in self.albums.values_list()]
    return str(join(lst, ', '))

def thumbnail_(self):
    return """<a href="/media/%s"><img border="0" alt="" src="/media/%s" /></a>""" % (
                                                        (self.image.name, self.thumbnail.name))
thumbnail.allow_tags = Trueenter code here
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ADMIN

class ImageAdmin(admin.ModelAdmin):
    # search_fields = ["title"]
    list_display = ["__unicode__", "title", "user", "rating", "size",  "tags_","albums_",
    "thumbnail", "created"]
list_filter = ["tags", "albums", "user"]

def save_model(self, request, obj, form, change):
    obj.user = request.user
    obj.save()
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我知道有更多有效的方法在Django中使用图像缩略图但是我想知道为什么当以这种方式使用缩略图时我一直得到这个Permission错误.

非常感谢所有帮助.谢谢.

mik*_*kej 6

我认为这NamedTemporaryFile取决于Windows上的行为.从文档:

此函数与TemporaryFile()完全相同,只是保证文件在文件系统中具有可见名称(在Unix上,目录条目未取消链接).可以从文件对象的名称成员中检索该名称.名称是否可以用于第二次打开文件,而命名的临时文件仍然是打开的,因此不同平台(它可以在Unix上使用;它不能在Windows NT或更高版本上使用).

(强调我的)

在线:

im.save(tf2.name, "JPEG")
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save 大概试图打开文件,以便它可以写入它.

PIL文档中,您可以传递save文件对象而不是文件名,因此将上面的内容替换为

im.save(tf2, "JPEG")
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可能有帮助.