使用jq获取JSON中数组元素的索引

Question

我有以下类型的json:

{
  "foo": "hello",
  "bar": [
    {
      "key": "k1",
      "val": "v1"
    },
    {
      "key": "k2",
      "val": "v2"
    },
    {
      "key": "k3",
      "val": "v3"
    }
  ]
}

我想输出以下内容:

"hello", 1, "k1", "v1"
"hello", 2, "k2", "v2"
"hello", 3, "k3", "v3"

我正在使用jq转换这个,答案也应该是jq转换.

我目前在:

echo '{"foo": "hello","bar": [{"key": "k1","val": "v1"},{"key": "k2","val": "v2"},{"key": "k3","val": "v3"} ]}' | jq -c -r '.bar[] as $b | [.foo, ($b | .key, .val)] | @csv'

这给了我:

"hello","k1","v1"
"hello","k2","v2"
"hello","k3","v3"

我怎样才能获得索引来显示正在解析的数组元素？

Answer 1

您可以将数组转换为条目以访问索引和值.然后,您可以构建CSV行.

$ jq -r '[.foo] + (.bar | to_entries[] | [.key+1,.value.key,.value.val]) | @csv' input.json
"hello",1,"k1","v1"
"hello",2,"k2","v2"
"hello",3,"k3","v3"