我想读取tomcat context.xml的参数
我想获得 context.xml 中的 companyName 值我null在编写下面提到的代码后获得了价值
请帮助我从context.xml. 你甚至可以告诉其他获取价值的方式context.xml
注意：不要说要写参数 web.xml
Context.xml (Tomcat 7)
<?xml version='1.0' encoding='utf-8'?>
<!--
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to You under the Apache License, Version 2.0
(the "License"); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
-->
<!-- The contents of this file will be loaded for each web application -->
<Context>
<!-- Default set of monitored resources -->
<WatchedResource>WEB-INF/web.xml</WatchedResource>
<!-- Uncomment this to disable session persistence across Tomcat restarts -->
<!--
<Manager pathname="" />
-->
<!-- Uncomment this to enable Comet connection tacking (provides events
on session expiration as well as webapp lifecycle) -->
<!--
<Valve className="org.apache.catalina.valves.CometConnectionManagerValve" />
-->
<Parameter name="companyName" value="My Company, Incorporated"
override="false"/>
</Context>
JSP(index.jsp)
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<%
ServletContext sc= getServletContext();
String testNameValue = sc.getInitParameter("companyName");
%>
<input type="text" value="<%=testNameValue%>">
</body>
</html>
输出
在实施下面给出的解决方案后更新
异常来了
小智 5
您不能以这种方式加载，因为context.xml是 JNDI 资源。请尝试以下方法：
Tomcat (context.xml)
<Parameter name="companyName" value="My Company, Incorporated" override="false"/>
Java端
InitialContext context = new InitialContext();
Context xmlNode = (Context) context.lookup("java:comp/env");
String companyName = (String) xmlNode.lookup("companyName");
Spring Side HomeController.java
@Controller
@RequestMapping("/")
public class HomeController {
@Autowired
private ServletContext servletContext;
@RequestMapping(method=RequestMethod.GET)
public ModelAndView index(ModelAndView mav) throws Exception {
String companyName = servletContext.getInitParameter("companyName");
mav.setViewName("home/index");
mav.addObject("companyName", companyName);
return mav;
}
public void setServletContext(ServletContext servletContext) {
this.servletContext = servletContext;
}
}
视图侧 index.jsp
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Home</title>
</head>
<body>
<c:out value="${companyName}"/>
</body>
</html>
上面的例子已经证明是成功的。我的脚本可以context.xml在运行时从文件中读取，如图所示。
- 你犯了一个错误。这不是“<Parameter ...>”而是“<Environment ...>”！！如果我们指定“<Parameter...”，我们需要以不同的方式访问变量：config.getServletContext().getInitParameter("companyName")。 (2认同)
| 归档时间： |
|
| 查看次数： |
12270 次 |
| 最近记录： |