从存储在变量中的字符串中获取对象数据

Alo*_*Jha 7 php class object

当对象名称(类别)直接放入时,它返回正确的值,如:

 $primary = $this->dbmapper->category['primary'] ;  // ( Correct Output )
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但是,当将对象名称放在名为$ dataname的变量中时,它返回空白,如:

 $dataname = 'category';
 $primary = $this->dbmapper->$dataname['primary'] ;   ( Blank Output )
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我的构造函数变量是:

  $this->dbmapper = $this->mapper();
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我的功能是:

  function mapper($module='')
    {
        $mapper =  array();
        $mapper['category']['table'] = 'allcategory';
        $mapper['category']['primary'] = 'categoryID';
        $mapper['page']['table'] = 'allpages';
        $mapper['page']['primary'] = 'pageID';
        return (object) $mapper;
    }
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Rom*_*est 5

要通过变量访问对象属性(特别是如果它是一个数组),请用括号括起来:

...
$dataname = 'category';
$primary = $this->dbmapper->{$dataname}['primary'];
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