为什么all.equal(1,2,3)返回TRUE

Question

我试过all.equal(1,2),它的平均差异为1.

为什么要all.equal(1,2,3)表演TRUE？

是因为如果它提供了两个以上的变量,它在不同的元素上运行.numeric()来检查它们的类型而不是数值差异？

Answer 1

因为1等于2,容差为3.来自docs:

  target: R object.

 current: other R object, to be compared with ‘target’.

     ...: Further arguments for different methods, notably the
          following two, for numerical comparison:

tolerance: numeric >= 0.  Differences smaller than ‘tolerance’ are not
          reported.  The default value is close to ‘1.5e-8’.

你的3是第三个参数,因此成为容忍.