如何处理来自多个活动的getResults？

Question

我试图从android studio的意图中获得结果.

在我的主要部分,我开始一项活动并使用 startActivityForResult(intent, 1)

然后我在活动2的mainActivity中使用get结果 setResults()

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == 1) {
        if(resultCode == RESULT_OK){
            Bundle extras = data.getExtras();
            if (extras != null) {
                String name = extras.getString("FIRSTNAME");
                String Lname = extras.getString("LASTNAME");
                int ID = extras.getInt("ID");

                //TODO: Get the list fragment to newinstance with out new arraylist

                Person p = new Person(name, Lname, ID);
                people.add(p);
                getFragmentManager().beginTransaction().replace(R.id.content_main, FullList.newInstance(people)).commit();
            }

在活动1的片段中,我称之为新的 startActivityForResult(i, 2)

如何让我的主要活动setResults() 从活动3中获取？

活动3正在这样做:

Intent deleteIntent = new Intent();
deleteIntent.putExtra("FNAME", first);
deleteIntent.putExtra("LNAME", last);
deleteIntent.putExtra("ID", num);
setResult(RESULT_OK, deleteIntent);
finish();

我正在尝试进行主要活动 if (requestCode == 2)

但它无济于事.

以下是所有onActivityResult供参考:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == 1) {
        if(resultCode == RESULT_OK){
            Bundle extras = data.getExtras();
            if (extras != null) {
                String name = extras.getString("FIRSTNAME");
                String Lname = extras.getString("LASTNAME");
                int ID = extras.getInt("ID");

                //TODO: Get the list fragment to newinstance with out new arraylist

                Person p = new Person(name, Lname, ID);
                people.add(p);

                getFragmentManager().beginTransaction().replace(R.id.content_main, FullList.newInstance(people)).commit();
            }

            // NOW SEEING IF THE DETAILS SCREEN PASSED BACK RESULTS

        } else if (requestCode == 2) {
            if (resultCode == RESULT_OK) {
                Bundle extras = data.getExtras();
                if (extras != null) {
                    String name = extras.getString("FNAME");
                    String Lname = extras.getString("LNAME");
                    int ID = extras.getInt("ID");

                    Person p = new Person(name, Lname, ID);
                    // Delete happens here //
                    if (people.contains(p)) {
                        people.remove(p);
                        // If empty show blank frag, if not, update list //
                        if (people.isEmpty()) {
                            getFragmentManager().beginTransaction().replace(R.id.content_main, BlankList.newInstance());
                        } else {
                            getFragmentManager().beginTransaction().replace(R.id.content_main, FullList.newInstance(people)).commit();
                        }

                    } else {
                        Toast.makeText(this, "DIDNT RECEIVE SAME INFO", Toast.LENGTH_SHORT).show();
                    }
                }
            }
        }
        // END ELSE CHECK
    }
}

这是startActivityForResult()在活动1的片段中调用的代码.

@Override
public void onListItemClick(ListView l, View v, int position, long id) {
    //super.onListItemClick(l, v, position, id);

    ArrayList<Person> people = (ArrayList<Person>) getArguments().getSerializable(ARG_People);

    if (people != null && position != -1) {
        Person listPerson = people.get(position);
        Intent i = new Intent("OPENDETAILS");
        i.putExtra("NAME", listPerson.name);
        i.putExtra("LASTNAME", listPerson.lName);
        i.putExtra("ID", listPerson.ID);
        startActivityForResult(i, 2);
    } else {
        Toast.makeText(getActivity(), "EMPTY LIST ERROR", Toast.LENGTH_SHORT).show();
    }
}

Answer 1

有点不清楚你要做什么,但听起来像是:

1. Activity1为结果启动Activity2
2. Activity2为结果启动Activity3
3. Activity3返回一个结果
4. Activity1预计会收到Activity3的结果.

如果我做对了,那么这里似乎缺少的关键元素就是你期望Activity1从Activity3获得一个结果,即使它是Activity2为结果启动它.在这种情况下,您应该onActivityResult在Activity2中实现,处理从Activity3返回的结果并将它们设置为Activity2的结果以传递回Activity1然后完成; 活动仅接收来自直接启动的活动的结果startActivityForResult.