Ama*_*les 0 java sql spring hibernate spring-mvc
我在Spring Web模型 - 视图 - 控制器(MVC)框架中有这个类.Spring Web模型 - 视图 - 控制器(MVC)框架的版本是3.2.8.
我在1 DAO中有这个方法
final StringBuilder queryString = new StringBuilder(" select app from Application app where upper (ticket_id) like :searchString and upper (id) like :searchString " );
queryString.append("where app.status != " + Status.READY.ordinal());
queryString.append(" order by app.submissionTime desc ");
try {
final Query query = getEntityManager().createQuery(queryString.toString());
searchString = searchString.replace("!", "!!")
.replace("%", "!%")
.replace("_", "!_")
.replace("[", "![")
.trim()
.toUpperCase();
query.setParameter ("searchString", searchString);
return query.getResultList();
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但我在运行时有这个错误:
org. where near line 1, column 144 [ select app from com.tdk.devices.domain.Application app where upper (ticket_id) like :searchString and upper (id) like :searchString where app.status != 0 order by app.submissionTime desc ]
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您使用了"where"子句2次.首先在StringBuilder的构造函数中,然后:
queryString.append("where app.status != " + Status.READY.ordinal());
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