如何在scala中实现相同的结果.
Map<String, Integer> lookup =
new TreeMap<String, Integer>(String.CASE_INSENSITIVE_ORDER);
lookup.put("One", 1);
lookup.put("tWo", 2);
lookup.put("thrEE", 3);
System.out.println(lookup.get("Two"));
System.out.println(lookup.get("three"));
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并不是因为你无法弄清楚它是如何"无法做同样的事情";)
scala> scala.collection.immutable.SortedMap("foo" -> "bar")(Ordering.by(_.toLowerCase)).get("Foo")
res10: Option[String] = Some(bar)
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