Eng*_*adi 5 html javascript input keypress
我的代码完美地改变了页面加载时自动输入的值,并且它之间有延迟.
但是还有另外一个问题,当我试图模拟按下[enter]输入上的键时,它不起作用,它提交表单并重新加载我的页面.
我如何模拟按下[enter]输入中的键而不提交表单而不重新加载我的页面?我用纯javascript无jQuery
这是我的脚本:
var form = document.querySelectorAll("._k3t69");
var input = document.querySelectorAll("._7uiwk._qy55y");
var message = "Replacement..." ;
var maxMsg = 3 ;
var delay = 2.5 * 1000 ; // 2.5 Seconds
var j = 0, k = 0;
function setValue(){
if( j == maxMsg || j == input.length) {
clearInterval(looping)
} else {
input[j++].value = message ;
//And then simulate pressing enter key ON THE INPUT, not sumbit the form
form[k++].submit();
}
}
var looping = setInterval(setValue, delay);Run Code Online (Sandbox Code Playgroud)
<form class="_k3t69">
<input type="text" class="_7uiwk _qy55y">
</form>
<form class="_k3t69">
<input type="text" class="_7uiwk _qy55y">
</form>
<form class="_k3t69">
<input type="text" class="_7uiwk _qy55y">
</form>Run Code Online (Sandbox Code Playgroud)
默认情况下提交表单将提交表单并重新加载页面.
如果要触发按键事件:
var input = document.querySelector("._7uiwk._qy55y");
var ev = document.createEvent('Event');
ev.initEvent('keypress');
ev.which = ev.keyCode = 13;
input.dispatchEvent(ev);
Run Code Online (Sandbox Code Playgroud)
如果要检查是否输入了按键:
var input = document.querySelector("._7uiwk._qy55y");
input.addEventListener('keypress', function(ev){
if(ev.keyCode === 13 || ev.which === 13){
// enter was pressed
}
});
Run Code Online (Sandbox Code Playgroud)
如果您想阻止在输入/提交时提交表单:
var form = document.querySelector("._k3t69");
form.addEventListener('submit', function(ev){
ev.preventDefault();
// you can do something alternative here e.g. send AJAX request to server
return false;
});
Run Code Online (Sandbox Code Playgroud)