She*_*man 1 selenium xpath selenium-firefoxdriver selenium-webdriver
这是我使用Firebug检查元素时的样子
当我在xpath中尝试相同的语法时,它选择结果页面2.我在selenium IDE中尝试了相同的方法并单击了find,它在执行代码时选择结果页面2.我正在接受No Such Element异常
Xpath语法: //a[contains(@href,'/jobs?q=qa+engineer&l=Renton%2C+WA&start=10')]/span[contains(@class,'pn')][text()='2']
public void jobSearch(){
WebDriver driver= new FirefoxDriver();
driver.get("https://www.indeed.com");
driver.findElement(By.id("what")).sendKeys("QA Engineer");
driver.findElement(By.id("where")).clear();
driver.findElement(By.id("where")).sendKeys("Seattle,WA");
driver.findElement(By.id("fj")).click();
driver.manage().timeouts().implicitlyWait(25, TimeUnit.SECONDS);
driver.findElement(By.xpath("//a[contains(@href,'/jobs?q=qa+engineer&l=Renton%2C+WA&start=10')]/span[contains(@class,'pn')][text()='2']")).click();
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感谢您的宝贵时间和宝贵的建议.
实际上有3个错误:
Selenium Webdriver脚本仅适用于Visible Area
方案:
添加步骤以向下滚动 网页
JavascriptExecutor jse = (JavascriptExecutor) driver;
jse.executeScript("window.scrollBy(0,1000)", "");
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Xpath不是一般化的.它用于获取在2num页面放置的URL .因此改变如下:
//div[@class='pagination']//span[text()='2']
有一些中断,如弹出,基于地区的网址.所以编写代码就像给定消除未来错误一样:
public void jobSearch() {
try{
WebDriver driver= new FirefoxDriver();
driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);
driver.manage().window().maximize();
driver.get("https://www.indeed.com");
try
{
//Here region based URL gets open so remove it if it is directly open www.indeed.com
driver.findElement(By.linkText("www.indeed.com")).click();
}
catch (Exception e)
{
}
driver.findElement(By.id("what")).sendKeys("QA Engineer");
driver.findElement(By.id("where")).clear();
driver.findElement(By.id("where")).sendKeys("Seattle,WA");
driver.findElement(By.id("fj")).click();
try
{
// After this one pop up gets open so close it
driver.findElement(By.xpath("//button[@id='prime-popover-close-button']/span")).click();
}
catch (Exception e)
{
}
//pageDown(driver.findElement(By.id("searchCount")), 2);
JavascriptExecutor jse = (JavascriptExecutor) driver;
jse.executeScript("window.scrollBy(0,1000)", "");
//driver.findElement(By.xpath("//a[contains(@href,'/jobs?q=qa+engineer&l=Renton%2C+WA&start=10')]/span[contains(@class,'pn')][text()='2']")).click();
driver.findElement(By.xpath("//div[@class='pagination']//span[text()='2']")).click();
// Now continue you code here
}
catch (Exception e)
{
e.printStackTrace();
} }
Run Code Online (Sandbox Code Playgroud)注意:请阅读GeckoDriver for Firefox和Chromedriver for Chrome浏览器使用Selenium 3.0+版本
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