Flask应用程序退出时如何停止Gunicorn

Pyt*_*ice 4 python linux flask gunicorn

我正在使用gunicorn运行我的Flask应用程序,但是当Flask应用程序由于错误而退出时,gunicorn将创建一个新的worker而不会退出。

Flask示例应用程序:

$ vim app.py

# main file
import sys
import os
import logging
from flask import Flask

from views import views

def create_app():

    app = Flask(__name__)

    app_name = os.environ.get('FLASK_APP_NAME', None)
    if app_name is None:
        logging.error("Failed to load configuration")
        sys.exit(2)

    app.config['APP_NAME'] = app_name

    console = logging.StreamHandler(sys.stdout)
    logging.getLogger().addHandler(console)
    logging.getLogger().setLevel(logging.INFO)

    logging.info("Starting Flask application")

    app.register_blueprint(views)

    return app

app = create_app()

if __name__ == '__main__':
    app.run(host='0.0.0.0', port=8000, debug=False, threaded=True)


$ vim views.py

# views
from flask import request, jsonify, Blueprint
from flask import current_app as app

views = Blueprint('views', __name__)

@views.route("/", methods=["GET"])
def indexz():
    return jsonify(app=app.config['APP_NAME'], msg='OK'), 200
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我尝试使用gunicorn的worker_exit服务器挂钩:

$ vim gunicorn-config.py

import sys

workers = 2

def worker_exit(server, worker):
    sys.exit(2)
    # server.halt()
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但这只会引发错误,并继续产生工作者:

# error when using sys.exit(2)
[2016-12-10 01:28:53 +0000] [11916] [INFO] Booting worker with pid: 11916
ERROR:root:Failed to load configuration
[2016-12-10 01:28:53 +0000] [11915] [INFO] Worker exiting (pid: 11915)
[2016-12-10 01:28:53 +0000] [11915] [WARNING] Exception during worker exit:
Traceback (most recent call last):
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 576, in spawn_worker
    self.cfg.worker_exit(self, worker)
  File "gunicorn-config.py", line 6, in worker_exit
    sys.exit(2)
SystemExit: 2


# error when using server.halt()
[2016-12-10 01:30:15 +0000] [12202] [INFO] Booting worker with pid: 12202
ERROR:root:Failed to load configuration
[2016-12-10 01:30:15 +0000] [12197] [INFO] Worker exiting (pid: 12197)
[2016-12-10 01:30:15 +0000] [12197] [INFO] Shutting down: Master
[2016-12-10 01:30:15 +0000] [12197] [WARNING] Exception during worker exit:
Traceback (most recent call last):
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 576, in spawn_worker
    self.cfg.worker_exit(self, worker)
  File "gunicorn-config.py", line 7, in worker_exit
    server.halt()
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 331, in halt
    self.stop()
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 378, in stop
    self.kill_workers(sig)
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 600, in kill_workers
    self.kill_worker(pid, sig)
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 616, in kill_worker
    self.cfg.worker_exit(self, worker)
  File "gunicorn-config.py", line 7, in worker_exit
    server.halt()
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 338, in halt
    sys.exit(exit_status)
SystemExit: 0
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编辑:将我的应用程序的退出代码修改为:sys.exit(4)按照https://github.com/benoitc/gunicorn/blob/master/gunicorn/arbiter.py#L37。这次应用程序不会无限重启,但是当有两个或更多工作程序时,将引发异常:

[2016-12-10 18:45:52 +0000] [22195] [INFO] Worker exiting (pid: 22195)
Traceback (most recent call last):
  File "/usr/bin/gunicorn", line 11, in <module>
    sys.exit(run())
  File "/usr/lib/python2.7/site-packages/gunicorn/app/wsgiapp.py", line 74, in run
    WSGIApplication("%(prog)s [OPTIONS] [APP_MODULE]").run()
  File "/usr/lib/python2.7/site-packages/gunicorn/app/base.py", line 192, in run
    super(Application, self).run()
  File "/usr/lib/python2.7/site-packages/gunicorn/app/base.py", line 72, in run
    Arbiter(self).run()
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 218, in run
    self.halt(reason=inst.reason, exit_status=inst.exit_status)
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 331, in halt
    self.stop()
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 381, in stop
    time.sleep(0.1)
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 231, in handle_chld
    self.reap_workers()
  File "/usr/lib/python2.7/site-packages/gunicorn/arbiter.py", line 506, in reap_workers
    raise HaltServer(reason, self.WORKER_BOOT_ERROR)
gunicorn.errors.HaltServer: <HaltServer 'Worker failed to boot.' 3>
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如何在不触发任何异常的情况下退出应用程序。

Boj*_*vic 6

为了完整起见,请使用标准错误代码:https ://docs.python.org/3/library/errno.html#errno.EINTR

所以:

import sys, errno
sys.exit(errno.EINTR)
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per*_*oud 5

这退出了gunicorn:

sys.exit(4)
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  • 天哪,谢谢!那正是我在寻找的♥(尽管我会建议`sys.exit(4)`) (2认同)

Gra*_*ton 0

查看配置中的preload_appgunicorn选项。这会将您的应用程序加载到父级中。然后它应该能够引发异常并且gunicorn不会启动。