PL/SQL和日期间隔

Question

我有一个约会,我想打印那个日期的偏移量.我可以做这个:

dbms_output.put_line(to_char(g_startDate - interval '4' month ,'YYYY-MM-DD'));

它工作正常.问题是间隔是可变的.当我尝试这个:

dbms_output.put_line(to_char(g_startDate - interval g_dateOffsetAmt month ,'YYYY-MM-DD'));

我收到编译器错误.

我想这可能是因为g_dateOffsetAmt是一个integer让我尝试这样做:

dbms_output.put_line(to_char(g_startDate - interval to_char(g_dateOffsetAmt) month ,'YYYY-MM-DD'));

虽然我仍然遇到编译器错误说:

Error: PLS-00103: Encountered the symbol "TO_CHAR" when expecting one of the following:

          . ) , * @ & | = - +  at in is mod remainder not rem =>
          ..   or != or ~= >=  and or like
          LIKE2_ LIKE4_ LIKEC_ as between from using || member
           SUBMULTISET_
       The symbol "," was substituted for "TO_CHAR" to continue.
Line: 704

Error: PLS-00103: Encountered the symbol "MONTH" when expecting one of the following:

          . ( ) , * % & | = - +  at in is mod remainder not range
          rem => ..   or != or ~= >=  and or
          like LIKE2_ LIKE4_ LIKEC_ between || multiset member
          SUBMULTISET_
       The symbol "." was substituted for "MONTH" to continue.
Line: 704

还有其他方法可以做到这一点吗？

Answer 1

您可能希望使用NumToYMInterval函数

declare
  v_interval pls_integer := 4;
begin
  dbms_output.put_line( sysdate - NumToYMInterval( v_interval, 'month' ) );
end;
/