将C代码翻译为Assembly

jwi*_*l22 3 c x86 assembly masm irvine32

我需要将此C代码转换为汇编语言代码

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    int answer, i;
    int right, wrong;
    right = 0;
    wrong = 0;

    for(i =1; i < 11; i = i+1){
        printf("What is %d + %d? ", i,i);
        scanf( "%d", &answer);

        if(answer == i + 1) {
            printf("right!  ");
            right++;
        }
        else {
            printf("Sorry, you're wrong.    ");
            printf("The answer is %d.   ", i + 1);
            wrong++;
        }
    }
    printf("You got %d right and %d wrong. ", right, wrong );
    return 0;
}
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我真的只需要知道如何将变量与汇编语言中的字符串组合在一起,就像上面的C代码一样.我想我可以处理其他一切.有人可以告诉我.我是否必须使用某种参考[].

注意我正在使用MASM并使用Kip Irvine的汇编语言来处理x86处理器的第6版

更新继承我试图从回答者的答案之一写入MASM的代码我一直收到错误.就像我在使用Kip Irvine的汇编语言之前所说的那样我必须包含库链接INCLUDE Irvine32.inc

这是错误>>>> programb.obj:错误LNK2019:函数_main @ 0中引用的未解析的外部符号_scanf

包括Irvine32.inc

有人可以帮助我做到这一点

.data
string1 db "What is %d + %d?  ", 0
string2 db "%d", 0
string3 db "right!  ", 0
string4 db "Sorry, you're wrong.   The answer is %d", 10, 0
string5 db "You got %d right and %d wrong.", 10, 0


answer dd 0
right  dd 0
wrong  dd 0

.code
main PROC

   mov ebx, 1

L1:

   cmp ebx, 11
   je L2

   push 1
   push ebx
   mov edx,OFFSET string1
   call WriteString
   add esp, 12

   push answer
   mov edx,OFFSET string2
   call scanf
   add esp, 8

   inc ebx
   cmp answer, ebx
   jne L3

   push ebx
   mov edx,OFFSET string3
   call WriteString
   add esp, 8
   inc right

   jmp L1

L3:

   push ebx
   mov edx,OFFSET string4
   call WriteString
   add esp, 8
   inc  wrong

   jmp L1

L2:

   push  wrong
   push  right
   mov EDX,OFFSET string5
   call WriteString
   add esp, 12


   exit

main ENDP
END main

programb.obj : error LNK2019: unresolved external symbol _scanf referenced in function _main@0
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我很抱歉汇编语言代码....我不知道如何格式化它所以它更容易阅读....

Ant*_*sse 9

您可以使用-Sgcc标志来生成汇编代码: gcc myfile.c -S -o myfile.s

我的意思是这个汇编文件应该回答你的所有问题.

  • 然后他可以在静态模式下编译,但重新编码`printf()`将是一个地狱! (3认同)
  • ...并附加标志`-masm = intel`以获得一个看起来像MASM的代码(英特尔语法):`gcc -S -masm = intel myfile.c -o myfile.s` (2认同)

asv*_*kau 5

我很无聊,所以我为你做了这个.我使用的是NASM,而不是MASM.我假设EBX是被调用者保存的寄存器.代码不是特别好.:-)

section .data
answer: dd 0
right:  dd 0
wrong:  dd 0

section .text
extern printf
extern scanf
global main
main:

   push ebx
   mov ebx, 1

.loop_start:

   cmp ebx, 11
   je .loop_end

   push 1
   push ebx
   push .string0
   call printf
   add esp, 12

   push answer
   push .string1
   call scanf
   add esp, 8

   inc ebx
   cmp dword [answer], ebx
   jne .wrong

   push ebx
   push .string2
   call printf
   add esp, 8
   inc dword [right]

   jmp .loop_start

.wrong:

   push ebx
   push .string3
   call printf
   add esp, 8
   inc dword [wrong]

   jmp .loop_start

.loop_end:

   push dword [wrong]
   push dword [right]
   push .string4
   call printf
   add esp, 12

   pop ebx
   xor eax, eax
   ret

section .data

.string0:
   db "What is %d + %d?  ", 0
.string1:
   db "%d", 0
.string2:
   db "right!  ", 0
.string3:
   db "Sorry, you're wrong.   The answer is %d", 10, 0
.string4:
   db "You got %d right and %d wrong.", 10, 0
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