考虑这个计算数字因子的F#代码:
let n = 340339004337I
// A sequence of all factors:
let factors = seq { 1I .. n / 2I} |> Seq.filter (fun x -> n % x = 0I)
// Pull off the first factor from the sequence:
let factor =
if factors = seq [] then
n
else
factors |> Seq.nth 0
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换句话说,如果factors是空的,那么返回n.否则,从中拉出第一个元素factors.我们的目标是占1和之间的所有因素(N/2) ,和Ñ本身自1和Ñ总是因素Ñ.
该factors = seq []测试是行不通的.我通过看这个来达到这个语法:
> seq {1 .. 100} |> Seq.filter (fun x -> false) ;;
val it : seq<int> = seq []
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但是,我认为seq []实际上并不是一个空序列:
> Seq.empty = seq [] ;;
val it : bool = false
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如何测试序列是否为空?
Ste*_*owe 16
试试Seq.isEmpty.
if Seq.isEmpty yourSeqName then doSomething else doSomethingElse
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顺便说一句,Seq.empty创建一个空的Seq.它没有测试一个.