Tre*_*ell 3 .net c# xml xslt stream
这是一个很快的问题,我今天一直在抨击我的头脑.
我正在尝试将.Net数据集转换为XML流,使用内存中的xsl文件对其进行转换,然后将结果输出到新的XML文件.
这是目前的解决方案:
string transformXML = @"pathToXslDocument";
XmlDocument originalXml = new XmlDocument();
XmlDocument transformedXml = new XmlDocument();
XslCompiledTransform transformer = new XslCompiledTransform();
DataSet ds = new DataSet();
string filepath;
originalXml.LoadXml(ds.GetXml()); //data loaded prior
StringBuilder sb = new StringBuilder();
XmlWriter writer = XmlWriter.Create(sb);
transformer.Load(transformXML);
transformer.Transform(originalXml, writer); //no need to select the node
transformedXml.LoadXml(sb.ToString());
transformedXml.Save(filepath);
writer.Close();
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这是原始代码:
BufferedStream stream = new BufferedStream(new MemoryStream());
DataSet ds = new DataSet();
da.Fill(ds);
ds.WriteXml(stream);
StreamReader sr = new StreamReader(stream, true);
stream.Position = 0; //I'm not certain if this is necessary, but for the StreamReader to read the text the position must be reset.
XmlReader reader = XmlReader.Create(sr, null); //Problem is created here, the XmlReader is created with none of the data from the StreamReader
XslCompiledTransform transformer = new XslCompiledTransform();
transformer.Load(@"<path to xsl file>");
transformer.Transform(reader, null, writer); //Exception is thrown here, though the problem originates from the XmlReader.Create(sr, null)
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由于某些原因在transformer.Transform方法中,读者没有根节点,实际上读者没有从StreamReader中读取任何内容.
我的问题是这段代码有什么问题?其次,有没有更好的方法将数据集转换/转换/存储到XML?
编辑:两个答案都很有帮助,技术上aku更接近.然而,我倾向于在尝试两种解决方案后更接近Longhorn的解决方案.
我不确定,但似乎你没有在将流传递给XmlReader之前重置流中的位置.在尝试从中读取之前,尝试在流的开头搜索.在向它写入一些数据后,可能还需要关闭\ flush stream.
编辑:
只是尝试了下面的代码,它完美地工作:
BufferedStream stream = new BufferedStream(new MemoryStream());
stream.Write(Encoding.ASCII.GetBytes("<xml>foo</xml>"), 0, "<xml>foo</xml>".Length);
stream.Seek(0, SeekOrigin.Begin);
StreamReader sr = new StreamReader(stream);
XmlReader reader = XmlReader.Create(sr);
while (reader.Read())
{
Console.WriteLine(reader.Value);
}
stream.Close();
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