找到两列之间具有最大差异的行

Question

我有一个带有列Gold和的数据框架Gold.1.我想找到这两列的差异最大的行.

对于以下DataFrame,这应该返回第6行.

df
Out: 
   Gold  Gold.1
0     2       1
1     1       4
2     6       9
3     4       4
4     4       8
5     5       5
6     5       2 ---> The difference is maximum (3)
7     5       9
8     5       3
9     5       6

我尝试使用以下内容:

df.where(max(df['Gold']-df['Gold.1']))

但是这引发了一个ValueError:

df.where(max(df['Gold']-df['Gold.1']))
Traceback (most recent call last):

  File "", line 1, in 
    df.where(max(df['Gold']-df['Gold.1']))

  File "../python3.5/site-packages/pandas/core/generic.py", line 5195, in where
    raise_on_error)

  File "../python3.5/site-packages/pandas/core/generic.py", line 4936, in _where
    raise ValueError('Array conditional must be same shape as '

ValueError: Array conditional must be same shape as self

如何找到满足此条件的行？

Answer 1

而不是.where,您可以使用.idxmax:

(df['Gold'] - df['Gold.1']).idxmax()
Out: 6

这将返回差异最大的索引.

如果要查找具有最大绝对差异的行,则可以.abs()先调用.

(df['Gold'] - df['Gold.1']).abs().idxmax()
Out: 4