在不使用desc的情况下显示sql中的最后5条记录

use*_*364 5 sql sql-server

我有这样的查询:

SELECT TOP 5
    CONVERT(varchar(15), CAST(Pout AS time), 100) AS 'OUT',
    CONVERT(varchar(15), CAST(pIn AS time), 100) AS 'IN',
    DATEDIFF(MINUTE, CONVERT(varchar(5), Pout, 108), CONVERT(varchar(5), pIn, 108)) AS [Total Used]
FROM 
    loginfo
WHERE 
    empid = 1001
    AND CONVERT(date, pDate) = '28/Nov/2016 2:45:00 PM'
    AND pOut IS NOT NULL
ORDER BY 
    pOut
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这个查询工作正常,但我不想显示前5条记录,我需要显示最近5条记录,我的意思是最后5条记录,但我不能ORDER BY pout DESC,因为我想以正确的格式显示报告,但我需要不使用降序显示我的交易的最后5条记录

例如,如果我有记录10事务,我想只显示正确格式的最后5条记录

sag*_*agi 5

ROW_NUMBER()改为使用:

SELECT * FROM (
    SELECT
          CONVERT(varchar(15), CAST(Pout AS time), 100) AS [OUT],
          CONVERT(varchar(15), CAST(pIn AS time), 100) AS [IN],
          DATEDIFF(MINUTE, CONVERT(varchar(5), Pout, 108),     
          CONVERT(varchar(5), pIn, 108)) AS [Total Used],
          ROW_NUMBER() OVER(ORDER BY pOut DESC) as rnk
    FROM loginfo
    WHERE empid = 1001
      AND CONVERT(date, pDate) = '28/Nov/2016 2:45:00 PM'
      AND pOut IS NOT NULL) p
WHERE p.rnk <= 5
ORDER BY What_Ever_You_Want
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或者,或者,使用派生表:

SELECT * FROM (Your Current Query)
ORDER BY pOut ;
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  • 先生,它似乎工作......我将再次检查并确认..谢谢 (2认同)