Mur*_*sli 5 search multidimensional-array typescript
我有一个简单的游戏,我试图找到两点之间的最短路线
该地图由二维数组组成matrix: Node[][],
class Node{
index: {
x: number,
y: number
},
isAvailable: boolean
}
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该算法应返回关于节点可用性的最短路径。
例如,树被标记为不可用node.isAvailable = false
我一直致力于实现这个矩阵的算法
我尝试从这里使用Dijkstras算法,但我不知道如何应用它,我做到了
const graph = new Dijkstra();
//convert the matrix (2d array) to graph
matrix.map((row) => {
row.map((node: Node) => {
let x = node.index.x;
let y = node.index.y;
graph.addVertex(x + ":" + y, {x: x, y: y});
});
});
console.log(graph.shortestPath('0:0', '5:5'));
//the output was ['0:0'] (definitly not the answer)
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如何将该算法应用于该矩阵?
PS这是我的完整代码
我必须实现 A* 算法
export class PathFinder {
grid: Tile[][];
gridHeight: number;
gridWidth: number;
startTile: Tile;
endTile: Tile;
/** Array of the already checked tiles. */
closedList: List<Tile> = new List<Tile>();
openList: List<Tile> = new List<Tile>();
constructor(grid: Tile[][], gridHeight: number, gridWidth: number) {
this.grid = grid;
this.gridHeight = gridHeight;
this.gridWidth = gridWidth;
}
searchPath(start: Tile, end: Tile): Tile[] {
this.startTile = start;
this.endTile = end;
/** Path validation */
if (!start.walkable) {
console.log('The start tile in not walkable, choose different tile than', start.index);
return [];
}
if (!end.walkable) {
console.log('The end tile in not walkable, choose different tile than', end.index);
return [];
}
/** Start A* Algorithm */
/** Add the starting tile to the openList */
this.openList.push(start);
let currentTile;
/** While openList is not empty */
while (this.openList.length) {
//current node = node for open list with the lowest cost.
currentTile = this.getTileWithLowestTotal(this.openList);
//if the currentTile is the endTile, then we can stop searching
if(JSON.stringify(currentTile.index) === JSON.stringify(end.index)){
this.startTile.setBackgroundColor("rgba(255, 45, 45, .8)");
this.endTile.setBackgroundColor("rgba(255, 45, 45, .8)");
return this.shortestPath();
}
else {
//move the current tile to the closed list and remove it from the open list.
this.openList.remove(currentTile);
this.closedList.push(currentTile);
// //Get all adjacent Tiles
let adjacentTiles = this.getAdjacentTiles(currentTile);
for (let adjacentTile of adjacentTiles) {
//Get tile is not in the open list
if (!this.openList.contains(adjacentTile)) {
//Get tile is not in the closed list
if (!this.closedList.contains(adjacentTile)) {
//move it to the open list and calculate cost
this.openList.push(adjacentTile);
//calculate the cost
adjacentTile.cost = currentTile.cost + 1;
//calculate the manhattan distance
adjacentTile.heuristic = this.manhattanDistance(adjacentTile);
// calculate the total amount
adjacentTile.total = adjacentTile.cost + adjacentTile.heuristic;
currentTile.setBackgroundColor('rgba(0, 181, 93, 0.8)');
}
}
}
}
}
}
getTileWithLowestTotal(openList: Tile[]): Tile {
let tileWithLowestTotal = new Tile();
let lowestTotal: number = 999999999;
/** Search open tiles and get the tile with the lowest total cost */
for (let openTile of openList) {
if (openTile.total <= lowestTotal) {
//clone lowestTotal
lowestTotal = openTile.total;
tileWithLowestTotal = openTile;
}
}
return tileWithLowestTotal;
}
getAdjacentTiles(current: Tile): Tile[] {
let adjacentTiles: Tile[] = [];
let adjacentTile: Tile;
//Tile to left
if (current.index.x - 1 >= 0) {
adjacentTile = this.grid[current.index.x - 1][current.index.y];
if (adjacentTile && adjacentTile.walkable) {
adjacentTiles.push(adjacentTile);
}
}
//Tile to right
if (current.index.x + 1 < this.gridWidth) {
adjacentTile = this.grid[current.index.x + 1][current.index.y];
if (adjacentTile && adjacentTile.walkable) {
adjacentTiles.push(adjacentTile);
}
}
//Tile to Under
if (current.index.y + 1 < this.gridHeight) {
adjacentTile = this.grid[current.index.x][current.index.y + 1];
if (adjacentTile && adjacentTile.walkable) {
adjacentTiles.push(adjacentTile);
}
}
//Tile to Above
if (current.index.y - 1 >= 0) {
adjacentTile = this.grid[current.index.x][current.index.y - 1];
if (adjacentTile && adjacentTile.walkable) {
adjacentTiles.push(adjacentTile);
}
}
/** TODO: Diagonal moves */
return adjacentTiles;
}
/** Calculate the manhattan distance */
manhattanDistance(adjacentTile: Tile): number {
return Math.abs((this.endTile.index.x - adjacentTile.index.x) +
(this.endTile.index.y - adjacentTile.index.y));
}
shortestPath() {
let startFound: boolean = false;
let currentTile = this.endTile;
let pathTiles = [];
//includes the end tile in the path
pathTiles.push(this.endTile);
this.endTile.ball = true;
while (!startFound) {
let adjacentTiles = this.getAdjacentTiles(currentTile);
//check to see what newest current tile.
for (let adjacentTile of adjacentTiles) {
//check if it is the start tile
if (JSON.stringify(adjacentTile.index) === JSON.stringify(this.startTile.index)){
return pathTiles;
}
//it has to be inside the closedList or openList
if (this.closedList.contains(adjacentTile) || this.openList.contains(adjacentTile)) {
if (adjacentTile.cost <= currentTile.cost && adjacentTile.cost > 0) {
//change the current tile.
currentTile = adjacentTile;
//Add this adjacentTile to the path list
pathTiles.push(adjacentTile);
//highlight way with yellow balls
adjacentTile.ball = true;
break;
}
}
}
}
}
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