C#将XML反序列化为对象

Question

将一些xml反序列化为C#中的对象时遇到问题.

我收到的错误是......

xmlns=''> was not expected.

我收到的用于生成课程的XSD如下......

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema targetNamespace="xml.AAAAAAA.com/commerce/apres-vente_technique/assistance" xmlns:pgp="xml.AAAAAAA.com/commerce/apres-vente_technique/assistance" xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified">
    <xs:element name="ListeAvisRemboursements">
        <xs:annotation>
            <xs:documentation>Liste des avis de remboursements</xs:documentation>
        </xs:annotation>
        <xs:complexType>
            <xs:sequence maxOccurs="unbounded">
                <xs:element name="AvisRemboursement" type="pgp:AvisRemboursementType"/>
            </xs:sequence>
        </xs:complexType>
    </xs:element>
    <xs:complexType name="AvisRemboursementType">
        <xs:annotation>
            <xs:documentation>Avis de remboursement lié à une DC</xs:documentation>
        </xs:annotation>
        <xs:sequence>

(剪断)

我尝试导入的文件如下:

<?xml version="1.0" encoding="UTF-8"?>
<ListeAvisRemboursements xmlns:ast="xml.AAAAAAA.com/commerce/apres-vente_technique/assistance">
    <ast:AvisRemboursement NumeroDT="3826961" CodeRA="020545G01" NumeroDC="1">
        <ast:DateTraitement>2010-06-22</ast:DateTraitement>
        <ast:MontantDC>25.0</ast:MontantDC>
        <ast:MontantMO>0.0</ast:MontantMO>
        <ast:SommeAD>25.0</ast:SommeAD>
        <ast:MontantPR>0.0</ast:MontantPR>
        <ast:SommePR>0.0</ast:SommePR>
        <ast:FraisGestion>0.0</ast:FraisGestion>
        <ast:NombreHeuresTotalRemboursees>0</ast:NombreHeuresTotalRemboursees>
        <ast:Etat>C</ast:Etat>
        <ast:NoteCredit>319984</ast:NoteCredit>
        <ast:Imputation>030</ast:Imputation>
        <ast:ListInterventionsPR/>
        <ast:ListInterventionsMO/>
    </ast:AvisRemboursement>

(剪断)

我认为正在发生的事情是,当.Net试图对xml进行去磁化时,它会触及包含"xmlns:ast"的第一行并对其进行投诉.据我所知,.Net将尝试将属性映射到目标类中的公共属性(并且它不会找到一个名为xmlns.或者我如何处理名称空间有问题.

我的反序列化代码如下所示:

    XmlDocument _Doc = new XmlDocument();
    _Doc.Load(@"C:\inputfile.xml");

    XmlSerializer _XMLSer = new XmlSerializer(typeof(ListeAvisRemboursements));
    ListeAvisRemboursements _X = (ListeAvisRemboursements)_XMLSer.Deserialize(new StringReader(_Doc.OuterXml));

我还尝试了将命名空间管理器添加到XML文档的各种组合.

XmlNamespaceManager _Ns = new XmlNamespaceManager(_Doc.NameTable);
_Ns.AddNamespace("ast", "xml.AAAAAAA.com/commerce/apres-vente_technique/assistance");

我知道有一种方法可以用它来告诉.Net接受哪些命名空间.

对于这个问题的一些帮助会很高兴.

---根据请求更新了类片段(抱歉应该包括之前)这是用xsd.exe创建的---

 /// <remarks/>
    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "xml.AAAAAAA.com/commerce/apres-vente_technique/assistance")]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "xml.AAAAAAA.com/commerce/apres-vente_technique/assistance", IsNullable = false)]
    public partial class ListeAvisRemboursements
    {

        private AvisRemboursementType[] avisRemboursementField;

        /// <remarks/>
        [System.Xml.Serialization.XmlElementAttribute("AvisRemboursement")]
        public AvisRemboursementType[] AvisRemboursement
        {
            get
            {
                return this.avisRemboursementField;
            }
            set
            {
                this.avisRemboursementField = value;
            }
        }
    }

    /// <remarks/>
    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(Namespace = "xml.AAAAAAA.com/commerce/apres-vente_technique/assistance")]
    public partial class AvisRemboursementType
    {

        private System.DateTime dateTraitementField;

        private double montantDCField;

        private double montantMOField;

        private double sommeADField;

        private double montantPRField;

Answer 1

没有完整的xsd/xml,或(或者)你的C#类,我们无法重现.但是从xml向上工作,这对我来说很好; 意思是:在您发布的代码/数据中,错误不是(据我所知).你能发布一个更完整(可重复)的例子吗？

public class ListeAvisRemboursements
{
    private readonly List<AvisRemboursement> items = new List<AvisRemboursement>();
    [XmlElement("AvisRemboursement", Namespace = "xml.AAAAAAA.com/commerce/apres-vente_technique/assistance")]
    public List<AvisRemboursement> Items { get { return items; } }
}
public class AvisRemboursement
{
    [XmlAttribute] public string NumeroDT {get;set;}
    [XmlAttribute] public string CodeRA {get;set;}
    [XmlAttribute] public string NumeroDC {get;set;}
    public DateTime DateTraitement { get; set; }
    public decimal MontantDC { get; set; }
    public decimal MontantMO { get; set; }
    public decimal SommeAD { get; set; }
    public decimal MontantPR { get; set; }
    public decimal SommePR { get; set; }
    public decimal FraisGestion { get; set; }
    public int NombreHeuresTotalRemboursees { get; set; }
    public string Etat { get; set; }
    public string NoteCredit { get; set; }
    public string Imputation { get; set; }
}
static void Main()
{
    var ser = new XmlSerializer(typeof(ListeAvisRemboursements));
    var wrapper = (ListeAvisRemboursements)ser.Deserialize(new StringReader(xml));
    // inspect wrapper.Items etc
}

也适用于:

var ser = new XmlSerializer(typeof(ListeAvisRemboursements));
using (var reader = XmlReader.Create("inputfile.xml"))
{
    var wrapper = (ListeAvisRemboursements)ser.Deserialize(reader);
}

和:

XmlDocument _Doc = new XmlDocument();
_Doc.Load("inputfile.xml");
var ser = new XmlSerializer(typeof(ListeAvisRemboursements));
var wrapper = (ListeAvisRemboursements)ser.Deserialize(new StringReader(_Doc.OuterXml));

和

XmlDocument _Doc = new XmlDocument();
_Doc.Load("inputfile.xml");
var ser = new XmlSerializer(typeof(ListeAvisRemboursements));
var wrapper = (ListeAvisRemboursements)ser.Deserialize(new XmlNodeReader(_Doc.DocumentElement));