Ale*_*erg 3 tensorflow tensorflow-serving
我用占位符训练模型is_training:
is_training_ph = tf.placeholder(tf.bool)
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但是一旦完成训练和验证,我想永久地false为这个值注入常数,然后"重新优化"图形(即使用optimize_for_inference).有什么东西freeze_graph会这样做吗?
一种可能性是使用tf.import_graph_def()函数及其input_map参数来重写图中该张量的值.例如,您可以按如下方式构建程序:
with tf.Graph().as_default() as training_graph:
# Build model.
is_training_ph = tf.placeholder(tf.bool, name="is_training")
# ...
training_graph_def = training_graph.as_graph_def()
with tf.Graph().as_default() as temp_graph:
tf.import_graph_def(training_graph_def,
input_map={is_training_ph.name: tf.constant(False)})
temp_graph_def = temp_graph.as_graph_def()
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构建之后temp_graph_def,您可以将其用作输入freeze_graph.
另一种可能freeze_graph与optimize_for_inference脚本(它们对变量名和检查点键做出假设)更兼容的替代方法是修改TensorFlow的graph_util.convert_variables_to_constants()函数,以便它转换占位符:
def convert_placeholders_to_constants(input_graph_def,
placeholder_to_value_map):
"""Replaces placeholders in the given tf.GraphDef with constant values.
Args:
input_graph_def: GraphDef object holding the network.
placeholder_to_value_map: A map from the names of placeholder tensors in
`input_graph_def` to constant values.
Returns:
GraphDef containing a simplified version of the original.
"""
output_graph_def = tf.GraphDef()
for node in input_graph_def.node:
output_node = tf.NodeDef()
if node.op == "Placeholder" and node.name in placeholder_to_value_map:
output_node.op = "Const"
output_node.name = node.name
dtype = node.attr["dtype"].type
data = np.asarray(placeholder_to_value_map[node.name],
dtype=tf.as_dtype(dtype).as_numpy_dtype)
output_node.attr["dtype"].type = dtype
output_node.attr["value"].CopyFrom(tf.AttrValue(
tensor=tf.contrib.util.make_tensor_proto(data,
dtype=dtype,
shape=data.shape)))
else:
output_node.CopyFrom(node)
output_graph_def.node.extend([output_node])
return output_graph_def
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...然后你可以training_graph_def像上面那样构建,并写道:
temp_graph_def = convert_placeholders_to_constants(training_graph_def,
{is_training_ph.op.name: False})
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