Pie*_*pon 1 c python pointers slice python-2.7
在C中,您可以通过执行以下操作来访问包含char地址的字符串中的所需位置:
&string[index]
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例如,这段代码:
#include <stdio.h>
int main()
{
char *foo = "abcdefgh";
printf("%s\n", &foo[2]);
}
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将返回:
cdefgh
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有没有办法在Python中做到这一点?
在Python中,它被称为字符串切片,语法是:
>>> foo = "abcdefgh"
>>> foo[2:]
'cdefgh'
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检查Python的String Document,它演示了切片功能以及python中字符串可用的其他功能.
我还建议看一下:在Python中剪切和切片字符串,其中演示了一些非常好的例子.
以下是与切片字符串相关的几个示例:
>>> foo[2:] # start from 2nd index till end
'cdefgh'
>>> foo[:3] # from start to 3rd index (excluding 3rd index)
'abc'
>>> foo[2:4] # start from 2nd index till 4th index (excluding 4th index)
'cd'
>>> foo[2:-1] # start for 2nd index excluding last index
'cdefg'
>>> foo[-3:-1] # from 3rd last index to last index ( excluding last index)
'fg'
>>> foo[1:6:2] # from 1st to 6th index (excluding 6th index) with jump/step of "2"
'bdf'
>>> foo[::-1] # reverse the string; my favorite ;)
'hgfedcba'
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