访问Android中的资源文件

Question

我在/ res/raw /文件夹(/res/raw/textfile.txt)中有一个资源文件,我试图从我的Android应用程序中读取进行处理.

public static void main(String[] args) {

    File file = new File("res/raw/textfile.txt");

    FileInputStream fis = null;
    BufferedInputStream bis = null;
    DataInputStream dis = null;

    try {
      fis = new FileInputStream(file);
      bis = new BufferedInputStream(fis);
      dis = new DataInputStream(bis);

      while (dis.available() != 0) {
              // Do something with file
          Log.d("GAME", dis.readLine()); 
      }

      fis.close();
      bis.close();
      dis.close();

    } catch (FileNotFoundException e) {
      e.printStackTrace();
    } catch (IOException e) {
      e.printStackTrace();
    }
  }

我尝试了不同的路径语法但总是得到java.io.FileNotFoundException错误.如何访问/res/raw/textfile.txt进行处理？是File file = new File("res/raw/textfile.txt"); Android中的错误方法？

---

*答案:*

// Call the LoadText method and pass it the resourceId
LoadText(R.raw.textfile);

public void LoadText(int resourceId) {
    // The InputStream opens the resourceId and sends it to the buffer
    InputStream is = this.getResources().openRawResource(resourceId);
    BufferedReader br = new BufferedReader(new InputStreamReader(is));
    String readLine = null;

    try {
        // While the BufferedReader readLine is not null 
        while ((readLine = br.readLine()) != null) {
        Log.d("TEXT", readLine);
    }

    // Close the InputStream and BufferedReader
    is.close();
    br.close();

    } catch (IOException e) {
        e.printStackTrace();
    }
}

Answer 1

如果您res/raw/textfile.txt的Activity/Widget调用中有一个文件:

getResources().openRawResource(...) 返回一个 InputStream

该点实际上应该是在R.raw发现了一个整数...对应的文件名,可能R.raw.textfile(这通常是不带扩展名的文件名)

new BufferedInputStream(getResources().openRawResource(...)); 然后以流的形式读取文件的内容