Ken*_*ake 5 html php html-table
我必须在桌子内使用for循环制作菱形星号.它必须<td>在星号之前和之后有"空白" 空间才能移动并使其看起来居中,因此它看起来像钻石.我怎么做?(我在HTML代码中使用了PHP.)
没有<tr>和<td>标签的代码,它看起来像钻石,因为它是中心对齐的:
<center>
<?php
echo "<table border = 1>";
// loop for the pyramid
for($i = 1; $i <= 10; $i += 2) {
for($j = 1; $j <= $i; $j++) {
echo "* ";
}
echo "<br />";
}
// loop for the inverted pyramid, so it looks like a diamond
for($i = 7; $i >= 1; $i -= 2) {
for($j = 1; $j <= $i; $j++) {
echo "* ";
}
echo "<br />";
}
echo "</table>";
?>
</center>
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带有<tr>和<td>标签的代码,需要"空格"才能看起来像是中心对齐的:
<?php
echo "<table border = 1>";
// loop for the pyramid
echo "<tr>";
for($i = 1; $i <= 10; $i += 2) {
echo "<tr>";
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
echo "</tr>";
}
echo "</tr>";
// loop for the inverted pyramid, so it looks like a diamond
for($i = 7; $i >= 1; $i -= 2) {
echo "<tr>";
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
echo "<br />";
echo "</tr>";
}
echo "</table>";
?>
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请帮忙!
这是包含您的解决方案的新代码。我添加了逻辑将空白 td 向前和向后放置到 *
<?php
echo "<table border = 1>";
// loop for the pyramid
echo "<tr>";
$max = $initAmount = 10;
for($i = 1; $i <= $initAmount; $i += 2) {
$max = $max -2;
$halfTD = (int)$max/2;
echo "<tr>";
for($b = 1; $b <= $halfTD; $b++){
echo "<td></td>";
}
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
for($b = 1; $b <= $halfTD; $b++){
echo "<td></td>";
}
echo "</tr>";
}
echo "</tr>";
// loop for the inverted pyramid, so it looks like a diamond
$max = $initAmount = 10;
for($i = 7; $i >= 1; $i -= 2) {
$max = $max -2;
$diff = $initAmount - $max;
$blankTd = $diff/2;
echo "<tr>";
for($b = 1 ; $b <= $blankTd; $b++){
echo "<td></td>";
}
for($j = 1; $j <= $i; $j++) {
echo "<td>* </td>";
}
for($b = 1 ; $b <= $blankTd; $b++){
echo "<td></td>";
}
echo "</tr>";
}
echo "</table>";
?>
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