如何快速过滤具有其他数组值的结构数组？

Question

我已经搜索过这个问题，但没有找到任何适用于我使用最新版本的 Xcode 和 Swift 的解决方案。我使用三个数组：

1. baseArray[Meal]: array filled with every meal. Not locally saved.

2. favoritesArray[Favorite]: with names of all favorite meals, locally saved by the user with NSKeyedArchiver.
3. filteredArray[Meal]: baseArray but filtered for searchterm. In code: 

    (filteredArray = baseArray.filter { $0.type == searchtext }}

我使用tableView. 如果他们想查看所有餐点，filteredArray则与baseArray.

我的问题：我怎么能得到filteredArray它有所有最喜欢的饭菜（所以在哪里Meal.title == Favorite.name）。我如何组合三个数组？

上周我尝试了很多选择，但都没有奏效..我希望你能帮助我！！

Answer 1

这做你想要的：

struct Meal {
  let title: String
}

struct Favorite {
  let name: String
}

let meal1 = Meal(title: "Soup")
let meal2 = Meal(title: "Stew")
let meal3 = Meal(title: "Pizza")

let favorite1 = Favorite(name: "Stew")

let baseArray = [meal1, meal2, meal3]
let favoritesArray = [favorite1]

let favoriteNames = favoritesArray.map { $0.name }

let filteredArray = baseArray.filter { favoriteNames.contains($0.title) }