计算PHP中邮政编码之间的距离

Question

计算PHP中邮政编码之间的距离

Cli*_*ote 23 php mysql algorithm math distance

我从这个页面中抓取了一个邮政编码数据库及其经纬度等 .它有以下字段:

ZIP,LATITUDE,LONGITUDE,CITY,STATE,COUNTY,ZIP_CLASS

数据在文本文件中,但我将其插入MySQL表中.我现在的问题是,我如何利用上面的字段来计算用户可以在网站上输入的两个邮政编码之间的距离？PHP中的工作代码将不胜感激

Answer 1

Ada*_*ire 24

这是迈克的答案,其中包含一些神奇数字的注释.对于一些测试数据,它似乎对我来说很好:

function calc_distance($point1, $point2)
{
    $radius      = 3958;      // Earth's radius (miles)
    $deg_per_rad = 57.29578;  // Number of degrees/radian (for conversion)

    $distance = ($radius * pi() * sqrt(
                ($point1['lat'] - $point2['lat'])
                * ($point1['lat'] - $point2['lat'])
                + cos($point1['lat'] / $deg_per_rad)  // Convert these to
                * cos($point2['lat'] / $deg_per_rad)  // radians for cos()
                * ($point1['long'] - $point2['long'])
                * ($point1['long'] - $point2['long'])
        ) / 180);

    return $distance;  // Returned using the units used for $radius.
}

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Answer 2

小智 7

它可以用数学来完成......

function calc_distance($point1, $point2)
{
    $distance = (3958 * 3.1415926 * sqrt(
            ($point1['lat'] - $point2['lat'])
            * ($point1['lat'] - $point2['lat'])
            + cos($point1['lat'] / 57.29578)
            * cos($point2['lat'] / 57.29578)
            * ($point1['long'] - $point2['long'])
            * ($point1['long'] - $point2['long'])
        ) / 180);

    return $distance;
}

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