rem*_*oys 0 html php ajax jquery
我通过执行Php函数从我的html页面发送邮件,我的index.html:
<form method="POST" action="sendmail.php" >
<input type="text" name="sender_name" placeholder="Name" required="">
<input type="text" name="sender_email" placeholder="Email" required="">
<input type="text" name="subject" placeholder="Subject" required="">
<textarea placeholder="Message" name="message" required=""></textarea>
<input type="submit" name="send" value="SEND">
</form>
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我的sendmail.php:
<?php
if($_POST['send'] == 'SEND'){
$to = 'queries@mydomain.com';
$subject = $_POST['subject'];
$message = $_POST['message'];
$headers = "From: ".$_POST['sender_nam??e?']." <".$_POST['sender_em??ail??'].">\r\n"; $headers = "Reply-To: ".$_POST['sender_ema??il??']."\r\n";
$headers = "Content-type: text/html; charset=iso-8859-1\r\n";
'X-Mailer: PHP/' . phpversion();
mail($to, $subject, $message, $headers);
}
?>
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以上工作正常,但它也离开当前页面我想在当前页面执行上述方法,并根据这个问题和这个问题
我必须使用Ajax和jQuery?到目前为止我对他们一无所知我有这个:
////in my index.html
<button type="button">send mail</button>
<p></p>
<script type="text/javascript">
$(document).ready(function(){
$("button").click(function(){
$.ajax({
type: 'POST',
url: 'sendmail.php',
success: function(data) {
alert(data)
$("l").text(data);
}
});
});
});
</script>
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我知道上面的不正确&它不工作(目前它在弹出窗口中显示sendmail.php的文本)我怎样才能使它工作,以便我可以执行sendmail.php ???
更新:
的index.html
<form method="POST" id="myForm" action="sendmail.php">
<input type="text" name="sender_name" placeholder="Name" required="">
<input type="text" name="sender_email" placeholder="Email" required="">
<input type="text" name="subject" placeholder="Subject" required="">
<textarea placeholder="Message" name="message" required=""></textarea>
<input type="submit" name="send" value="SEND">
</form>
</div>
<script type="text/javascript">
$(document).ready(function(){
$("#myForm").on('submit', function(){
var formData = $(this).serialize();
$.ajax({
type: 'POST',
url: 'sendmail.php',
data: formData,
success: function(response.success) {
alert(response.success)
$("l").text(response.success);
}
});
});
</script>
`
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以下应该适合您使用.on('submit'和.serialize()
HTML
<form method="POST" id="myForm" action="sendmail.php">
<input type="text" name="sender_name" placeholder="Name" required="">
<input type="text" name="sender_email" placeholder="Email" required="">
<input type="text" name="subject" placeholder="Subject" required="">
<textarea placeholder="Message" name="message" required=""></textarea>
<input type="submit" name="send" value="SEND">
</form>
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JS
$(document).ready(function() {
$("#myForm").on('submit', function(event) {
event.preventDefault();
var formData = $(this).serialize();
$.ajax({
type: 'POST',
url: 'sendmail.php',
dataType: "json",
data: formData,
success: function(response) {
alert(response.success);
},
error: function(xhr, status, error){
console.log(xhr);
}
});
});
});
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PHP
<?php
if(isset($_POST['message'])){
$to = 'queries@mydomain.com';
$subject = $_POST['subject'];
$message = $_POST['message'];
$headers = "From: ".$_POST['sender_nam??e?']." <".$_POST['sender_em??ail??'].">\r\n"; $headers = "Reply-To: ".$_POST['sender_ema??il??']."\r\n";
$headers = "Content-type: text/html; charset=iso-8859-1\r\n";
'X-Mailer: PHP/' . phpversion();
if(mail($to, $subject, $message, $headers)) echo json_encode(['success'=>true]);
else echo json_encode(['success'=>false]);
exit;
}
?>
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