nuv*_*vio 25 rxjs angular2-observables angular
我在制作嵌套的Observable调用时遇到了一些麻烦.我的意思是调用一个http服务来检索用户,然后从用户获取id以进行另一个http调用,最后在屏幕上呈现结果.
1)HTTP GET 1:获取用户
2)HTTP GET 2:获取用户的首选项,将唯一标识符作为参数传递
这转换为组件中的以下代码Blah.ts:
版本1 - 此代码不显示任何内容
ngOnInit() {
this.userService.getUser()
.flatMap(u => {
this.user = u; // save the user
return Observable.of(u); // pass on the Observable
})
.flatMap(u => this.userService.getPreferences(this.user.username)) // get the preferences for this user
.map(p => {
this.preferences = p; // save the preferences
});
}
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版本2 - 此代码有效,但对我来说似乎是错误的方法:
this.userService.getUser().subscribe(u => {
this.user = u;
this.userService.getPreferences(this.user.username).subscribe(prefs => {
this.preferences = prefs;
});
});
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这是模板:
<h3>User</h3>
<div class="row col-md-12">
<div class="col-md-6">
<div class="panel panel-default">
<div class="panel-heading">
<h3 class="panel-title">User details</h3>
</div>
<div class="panel-body">
<table class="table table-condensed">
<thead>
<tr>
<th>Username</th>
<th>Full Name</th>
<th>Enabled</th>
</tr>
</thead>
<tbody>
<tr>
<td>{{user?.username}}</td>
<td>{{user?.fullName}}</td>
<td>{{user?.enabled}}</td>
</tr>
</tbody>
</table>
</div>
</div>
</div>
<!-- end of col 1-->
<div class="col-md-6">
<div class="panel panel-default">
<div class="panel-heading">
<h3 class="panel-title">User preferences</h3>
</div>
<div class="panel-body">
<table class="table table-condensed">
<thead>
<tr>
<th>Language</th>
<th>Locale</th>
</tr>
</thead>
<tbody>
<tr>
<td>{{preferences?.preferences?.get('language')}}</td>
<td>{{preferences?.preferences?.get('locale')}}</td>
</tr>
</tbody>
</table>
</div>
</div>
</div>
<!-- end of col 2-->
</div>
<!-- end of row 1-->
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我不认为展示服务有任何意义,只需http get()拨打电话:
http.get('http://blablah/users/')
.map((response) => response.json())
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请建议哪个是定义Observable链的最佳工作方法.
j2L*_*L4e 34
你应该读一下rxjs的运算符.您的示例非常详细和使用,flatMap并且map在某种程度上它们不应该被使用.你的第一个例子也行不通,因为你没有订阅Observable.
这将满足您的需求:
ngOnInit() {
this.userService.getUser()
.do(u => this.user = u) //.do just invokes the function. does not manipulate the stream, return value is ignored.
.flatMap(u => this.userService.getPreferences(u.username))
.subscribe(p => this.preferences = p);
}
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从rxjs 5.5开始,您应该使用可管道运算符:
ngOnInit() {
this.userService.getUser().pipe(
tap(u => this.user = u),
flatMap(u => this.userService.getPreferences(u.username))
).subscribe(p => this.preferences = p);
}
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好吧,所以经过一天的互联网挣扎和编译信息后,我学到了关于链接Observables(按序列调用Observables - 一个接一个)的知识:
我正在开发一个Angular2(4)网站,该网站使用java后端API来获取/设置/修改数据库中的信息.
我的问题是我必须在返回Observables(RxJS)的序列中进行两次API(HTTP POST)调用.
我有Operation1和Operation2.操作2应在操作1完成后执行.

Variant1 - >起初我在其他内部做了一个(比如javascript中的嵌套函数):
this.someService.operation1(someParameters).subscribe(
resFromOp1 => {
this.someService.operation2(otherParameters).subscribe(
resFromOp2 => {
// After the two operations are done with success
this.refreshPageMyFunction()
},
errFromOp2 => {
console.log(errFromOp2);
}
);
},
errFromOp1 => {
console.log(errFromOp1);
}
);
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尽管这些代码是合法且有效的,但我还是要求一个接一个地链接这些Observable,就像使用Promise的异步函数一样.一种方法是将Observables转换为Promises.
另一种方法是使用RxJS flatMap:
Variant2 - >另一种方法是用flatMap做这个,据我所知,它类似于Promises:
this.someService.operation1(someParameters)
.flatMap(u => this.someService.operation2(otherParameters))
.subscribe(function(){
return this.refreshPageMyFunction()
},
function (error) {
console.log(error);
}
);
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Variant3 - >与Arrow功能相同:
this.someService.operation1(someParameters)
.flatMap(() => this.someService.operation2(otherParameters))
.subscribe(() => this.refreshPageMyFunction(),
error => console.log(error)
);
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返回Observables的方法基本上是:
operation1(someParameters): Observable<any> {
return this.http.post('api/foo/bar', someParameters);
}
operation2(otherParameters): Observable<any> {
return this.http.post('api/some/thing', otherParameters);
}
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其他资源和有用的评论:
This post approved answer by @j2L4e: https://stackoverflow.com/a/40803745/2979938
https://stackoverflow.com/a/34523396/2979938
https://stackoverflow.com/a/37777382/2979938
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