use*_*088 4 mysql sql database left-join web
我有2个表(用户和信息)。我需要选择所有用户数据以及相关的最后插入的“ infotext”(insert_time)
表用户
+----+--------+----------+
| id | name | adress |
+----+--------+----------+
| 1 | Name 1 | Adress 1 |
| 2 | Name 2 | Adress 2 |
| 3 | user 3 | adress 3 |
| 4 | user 4 | adress 4 |
+----+--------+----------+
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表信息
+----+---------+----------+---------------------+
| id | id_user | infotext | insert_time |
+----+---------+----------+---------------------+
| 1 | 1 | info 1 | 2016-11-24 14:03:23 |
| 2 | 1 | info 2. | 2016-11-24 14:08:30 |
| 3 | 3 | text 3. | 2016-11-24 14:08:46 |
+----+---------+----------+---------------------+
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我当前的查询是:
SELECT a.*, b.infotext FROM user a LEFT JOIN infos b
ON a.id = b.id_user
LEFT JOIN
(
SELECT id_user, MAX(insert_time) newestInsert
FROM infos
GROUP BY id_user
) c ON c.id_user = b.id_user AND
c.newestInsert = b.insert_time
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但是问题是它输出的id并不唯一:
+----+--------+----------+----------+
| id | name | adress | infotext |
+----+--------+----------+----------+
| 1 | Name 1 | Adress 1 | info 1 |
| 1 | Name 1 | Adress 1 | info 2. |
| 3 | user 3 | adress 3 | text 3. |
| 2 | Name 2 | Adress 2 | NULL |
| 4 | user 4 | adress 4 | NULL |
+----+--------+----------+----------+
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我需要的最终结果是:
+----+--------+----------+----------+
| id | name | adress | infotext |
+----+--------+----------+----------+
| 1 | Name 1 | Adress 1 | info 2. |
| 3 | user 3 | adress 3 | text 3. |
| 2 | Name 2 | Adress 2 | NULL |
| 4 | user 4 | adress 4 | NULL |
+----+--------+----------+----------+
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将第二个条件放在on子句中。此方法将其作为相关子查询:
SELECT u.*, i.infotext
FROM user u LEFT JOIN
infos i
ON u.id = i.id_user and
i.insert_time = (SELECT MAX(i2.insert_time)
FROM infos i2
WHERE i2.id_user = i.id_user
);
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