在having子句中对多个组求和

Question

我有以下查询按保险类型显示计数.这是查询:

;WITH CTE
AS
(
SELECT DISTINCT ROW_NUMBER() OVER (Partition by PatInfo.PatientProfileID Order By E.Visit desc) AS RowNumber, 
        PatInfo.PatientProfileID, E.Visit, PatInfo.Zip, E.CarrierTypeDesc, E.FinancialClassDescription, IG.UDSInsuranceGroupName,IG.UDSInsuranceID
FROM Encounter E JOIN CHCEncounterType ET ON E.CHCEncounterTypeID = ET.CHCEncounterTypeID       
        JOIN PatientInfo PatInfo ON PatInfo.PatientProfileID = E.PatientProfileID
        LEFT JOIN dbo.UDSInsuranceMapping ON ISNULL(dbo.UDSInsuranceMapping.InsuranceName,'') = ISNULL(E.FinancialClassDescription,'') 
        LEFT JOIN dbo.UDSInsuranceGroups IG ON IG.UDSInsuranceID = dbo.UDSInsuranceMapping.UDSInsuranceID            
WHERE E.EncounterCounted = 1 
) 

SELECT Zip AS ZipCode, 
    Count(PatientProfileID) as Total, UDSInsuranceGroupName, UDSInsuranceID
from CTE 
where RowNumber = 1 AND ZIP IS NOT NULL 
group by Zip, UDSInsuranceGroupName, UDSInsuranceID 

返回的邮政编码数据示例如下:

Zip Code  Total InsuranceGroup             InsuranceID 
19522       9   Medicaid/CHIP/Other/Public      2 
19522       1   Medicare                        3 
19522       1   None/Uninsured                  1 
19522       1   Private                         4
19512       2   Medicaid/CHIP/Other/Public      2
19512       1   None/Uninsured                  1
19518       1   Medicaid/CHIP/Other/Public      2
19518       1   Medicare                        3

我想将显示限制为仅包含总数超过10的邮政编码.因此,19522将显示邮政编码,因为有12个,但另一个不会显示.如果我添加一个having条款,则不会显示19522 zip,因为其中一个保险类别中只有9个.我需要将每个邮政编码的所有保险类别加起来.

我怎样才能做到这一点？

Answer 1

您可以使用窗口函数,但这需要另一级子查询:

with . ..
select *
from (select Zip AS ZipCode, 
             Count(*) as Total, UDSInsuranceGroupName,
             UDSInsuranceID,
             sum(count(*)) over (partition by zip) as zipTotal
      from CTE 
      where RowNumber = 1 AND ZIP IS NOT NULL 
      group by Zip, UDSInsuranceGroupName, UDSInsuranceID 
     ) z
where zipTotal > 10;