Hibernate 5中不推荐使用createCriteria方法

fao*_*xis 53 java hibernate

此调用已弃用:

session.createCriteria(Bus.class).list();
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在源文件中,我可以看到:

/** @deprecated */
@Deprecated
Criteria createCriteria(Class var1);

/** @deprecated */
@Deprecated
Criteria createCriteria(Class var1, String var2);

/** @deprecated */
@Deprecated
Criteria createCriteria(String var1);

/** @deprecated */
@Deprecated
Criteria createCriteria(String var1, String var2);
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但我无法理解我必须使用哪种方法代替createCriteria.

Dim*_*San 70

您可以在Hibernate 5.2 +中使用以下界面:

javax.persistence.criteria.CriteriaBuilder
javax.persistence.criteria.CriteriaQuery

// Create CriteriaBuilder
CriteriaBuilder builder = session.getCriteriaBuilder();

// Create CriteriaQuery
CriteriaQuery<YourClass> criteria = builder.createQuery(YourClass.class);
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  • 对于真实代码和完整示例:[Giflib hibernate:使用JPA Criteria API更新到Hibernate 5.2](https://github.com/treehouse/giflib-hibernate/commit/f97a2828a466e849d8ae84884b5dce60a66cf412) (7认同)
  • 您可以使用`CriteriaQuery <T> where`方法.更多信息:https://docs.oracle.com/cd/E19798-01/821-1841/gjivi/index.html (4认同)

STE*_*EEL 12

截至2018年3月增加答案.

依赖关系:

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.boot.MetadataSources;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.hibernate.service.ServiceRegistry;

import javax.persistence.criteria.CriteriaQuery;
import java.util.List;



public static List<Contact> fecthAllContacts() {
        Session session = sessionFactory.openSession();

        // create Criteria
        CriteriaQuery<Contact> criteriaQuery = session.getCriteriaBuilder().createQuery(Contact.class);
        criteriaQuery.from(Contact.class);

        List<Contact> contacts = session.createQuery(criteriaQuery).getResultList();
        session.close();

        return contacts;
    }
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sessionFactory为:

public static SessionFactory buildSessionFactory() {
        final ServiceRegistry registry = new StandardServiceRegistryBuilder().configure().build();
        return new MetadataSources(registry).buildMetadata().buildSessionFactory();
    }
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jus*_*tMe 12

我有以下方法,出于安全原因更改了对象名称:

public List<MyObject> listAllForIds(List<Long> ids) {
    Criteria criteria = getSessionFactory().getCurrentSession().createCriteria(MyObject.class)
            .createAlias("joinObject", "joinObject")
            .add(Restrictions.not(Restrictions.like("name", "string1", MatchMode.END)))
            .add(Restrictions.not(Restrictions.like("name", "string2", MatchMode.END)))
            .add(Restrictions.in("joinObject.id", ids));

    return criteria.list();
}
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更改为使用:

javax.persistence.criteria.CriteriaBuilder
javax.persistence.criteria.CriteriaQuery
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该查询如下所示:

public List<MyObject> listAllForIds(List<Long> ids) {

    CriteriaBuilder builder = getSessionFactory().getCurrentSession().getCriteriaBuilder();
    CriteriaQuery<MyObject> criteria = builder.createQuery(MyObject.class);
    Root<MyObject> myObjectRoot = criteria.from(MyObject.class);
    Join<MyObject, JoinObject> joinObject = myObjectRoot.join("joinObject");

    Predicate likeRestriction = builder.and(
            builder.notLike( myObjectRoot.get("name"), "%string1"),
            builder.notLike( myObjectRoot.get("name"), "%string2")
    );

    criteria.select(myObjectRoot).where(joinObject.get("id").in(ids), likeRestriction);

    TypedQuery<MyObject> query = getSessionFactory().getCurrentSession().createQuery(criteria);

    return query.getResultList();
}
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希望它对其他人有帮助,请随时提出任何建议以改进代码。