ANDROID FirebaseDatabase:无法保存对象

Question

我无法向firebase实时数据库添加对象.我尝试了以下代码.但是当这段代码执行时

db.child("Users").setValue(person); 

我的应用程序崩溃了

public class Person{
   String fname;
   String lname;
   Person()
   {}
   Person(String fname,String lname)
   {
       this.fname = fname;
       this.lname = lname;
   }

   public String getFname() {
       return fname;
   }

   public String getLname() {
       return lname;
   }
}

这是错误.

11-20 15:34:57.762 2752-2752/shazdroid.com.surveyapp E/AndroidRuntime:FATAL EXCEPTION:main进程:shazdroid.com.surveyapp,PID:2752 com.google.firebase.database.DatabaseException:发现冲突的getter for name:isChangingConfigurations com.google.android.gms.internal.zzamy $ zza.(未知来源)com.google.android.gms.internal.zzamy.zzj(未知来源)com.google.android.gms.internal .zzamy.zzca(未知来源)com.google.android.gms.internal.zzamy.zzch(未知来源)com.google.android.gms.internal.zzamy $ zza.zzci(未知来源)com.google来自com.google.firebase.database.DatabaseReference.zza(未知来源)com.google.android.gms.internal.zzamy.zzbz(未知来源)的.android.gms.internal.zzamy.zzca(未知来源)位于shazdroid.com.surveyapp.AddMember.savePerson(AddMember.java:207)的.google.firebase.database.DatabaseReference.setValue(未知来源)位于shazdroid.com.surveyapp.AddMember.access $ 000(AddMember.java:37)at at shazdroid.com.surveyapp.AddMember $ 6.onClick(AddMember.java:193)在Android.view.Handler.handleCallback的android.view.View $ PerformClick.run(View.java:22260)的android.view.View.performClick(View.java:5610) (Handler.java:751)android.app.Handler.dispatchMessage(Handler.java:95)android.app.Looper.loop(Looper.java:154)android.app.ActivityThread.main(ActivityThread.java: 6077)位于com.android.internal.os.ZygoteInit.main的com.android.internal.os.ZygoteInit $ MethodAndArgsCaller.run(ZygoteInit.java:865)的java.lang.reflect.Method.invoke(Native Method)( ZygoteInit.java:755)

这是我如何保存对象.

    private void savePerson() {
    suc.show();
    Person person = new Person("shahbaz","ansari");
    db.child("User").setValue(person)
            .addOnCompleteListener(AddMember.this, new OnCompleteListener<Void>() {
        @Override
        public void onComplete(@NonNull Task<Void> task) {
            if(task.isSuccessful())
            {
                suc.dismissWithAnimation();
                suc = new SweetAlertDialog(AddMember.this,SweetAlertDialog.SUCCESS_TYPE);
                suc.setTitleText("Successful");
                suc.setContentText("Saving data successful");
                suc.setConfirmText("OK");
                suc.setConfirmClickListener(new SweetAlertDialog.OnSweetClickListener() {
                    @Override
                    public void onClick(SweetAlertDialog sweetAlertDialog) {
                        sweetAlertDialog.dismissWithAnimation();
                    }
                }).show();
            }else{
                suc.dismissWithAnimation();
                suc = new SweetAlertDialog(AddMember.this,SweetAlertDialog.ERROR_TYPE);
                suc.setTitleText("Failed");
                suc.setContentText("Failed to save data");
                suc.setConfirmText("Try Again");
                suc.setConfirmClickListener(new SweetAlertDialog.OnSweetClickListener() {
                    @Override
                    public void onClick(SweetAlertDialog sweetAlertDialog) {
                        savePerson();

                    }
                });
                suc.setCancelText("cancle");
                suc.setCancelClickListener(new SweetAlertDialog.OnSweetClickListener() {
                    @Override
                    public void onClick(SweetAlertDialog sweetAlertDialog) {
                        sweetAlertDialog.dismissWithAnimation();
                    }
                }).show();
            }
        }
    });

---

Answer 1

堆栈跟踪引用isChangingConfigurations,这是方法的名称Activity.这可能表明您已将类声明Person为活动的内部类.当Firebase序列化时,Person它还会尝试序列化封闭的Activity类并失败.

将声明移动Person到包级别或更改声明以使其成为静态内部类:public static class Person.