Jua*_*eza 40
如果你有这张桌子
表格1:
Field1 Field2 Field3
---------------------------
1 1 1
NULL NULL NULL
2 2 NULL
1 3 1
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然后
SELECT COUNT(*), COUNT(Field1), COUNT(Field2), COUNT(DISTINCT Field3)
FROM Table1
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输出是:
COUNT(*) = 4; -- count all rows, even null/duplicates
-- count only rows without null values on that field
COUNT(Field1) = COUNT(Field2) = 3
COUNT(Field3) = 2
COUNT(DISTINCT Field3) = 1 -- Ignore duplicates
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