JSe*_*ter 8 promise typescript angular
我在Angular2服务中有一个函数,它返回Mock数据Promise.resolve
,当解包时.then
给我一个空的promise对象.我可以看到调用函数在__zone_symbole__value
传递到.then however inside of
.then 之前在属性中接收带有有效负载的PromiseI seem to be left with just an empty promise.
getTemperatureData(): Promise<any> {
let data = this.convertJSONToGoogleChartTable(temperatureData_JSON);
let p = Promise.resolve(data);
return p;
}
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使用Chrome我看到上面的p看起来像
ZoneAwarePromise {__zone_symbol__state: true, __zone_symbol__value: "[["Date","Temperature","LowTemperature"],["05/11/2…",69.02,null],["06/11/2016 23:54:34",69.99,null]]"}
调用代码分为两行进行调试.
getTemperatureData() {
var d = this.dataService.getTemperatureData();
d.then(data => this.line_ChartData = data);
}
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当我看到d时,我看到与上面的p相同
ZoneAwarePromise {__zone_symbol__state: true, __zone_symbol__value: "[["Date","Temperature","LowTemperature"],["05/11/2…",69.02,null],["06/11/2016 23:54:34",69.99,null]]"}
问题发生.then
在"d"的值只是一个空的承诺的地方.以下内容取自Chrome开发工具控制台,以显示我所看到的内容.
d.then(data => console.log(data))
ZoneAwarePromise {__zone_symbol__state: null, __zone_symbol__value: Array[0]}
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无论我做了什么以及我尝试了多少组合,我都无法获得d中的数据.(注意,p和d只是临时破坏代码的.)
我的package.json如下:
{
"name": "angular2",
"version": "0.0.0",
"license": "MIT",
"angular-cli": {},
"scripts": {
"start": "ng serve",
"lint": "tslint \"src/**/*.ts\"",
"test": "ng test",
"pree2e": "webdriver-manager update",
"e2e": "protractor"
},
"private": true,
"dependencies": {
"@angular/common": "~2.1.0",
"@angular/compiler": "~2.1.0",
"@angular/core": "~2.1.0",
"@angular/forms": "~2.1.0",
"@angular/http": "~2.1.0",
"@angular/material": "^2.0.0-alpha.9-3",
"@angular/platform-browser": "~2.1.0",
"@angular/platform-browser-dynamic": "~2.1.0",
"@angular/router": "~3.1.0",
"core-js": "^2.4.1",
"ng2-bootstrap": "^1.1.16",
"node-mysql": "^0.4.2",
"rxjs": "5.0.0-beta.12",
"ts-helpers": "^1.1.1",
"zone.js": "^0.6.23"
},
"devDependencies": {
"@types/jasmine": "^2.2.30",
"@types/node": "^6.0.42",
"angular-cli": "1.0.0-beta.19-3",
"codelyzer": "1.0.0-beta.1",
"jasmine-core": "2.4.1",
"jasmine-spec-reporter": "2.5.0",
"karma": "1.2.0",
"karma-chrome-launcher": "^2.0.0",
"karma-cli": "^1.0.1",
"karma-jasmine": "^1.0.2",
"karma-remap-istanbul": "^0.2.1",
"protractor": "4.0.9",
"ts-node": "1.2.1",
"tslint": "3.13.0",
"typescript": "~2.0.3",
"webdriver-manager": "10.2.5"
}
}
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数据的价值只是一个空洞的承诺
这告诉我这convertJSONToGoogleChartTable
是返回一个承诺,而你并没有将你的承诺链接到它上面。
请注意,如果您使用比 更强的类型any
,TypeScript 编译器可能会为您捕获此问题。
由于您在获取数据后没有执行任何操作,因此您可以这样做:
getTemperatureData(): Promise<any> {
return this.convertJSONToGoogleChartTable(temperatureData_JSON);
}
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但是如果你想在返回数据之前对其进行一些操作,你可以在 a 中执行此操作then
,链接到原始承诺:
getTemperatureData(): Promise<any> {
return this.convertJSONToGoogleChartTable(temperatureData_JSON)
.then(data => {
console.log(data);
return data;
});
}
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