Auth::guard('user')->user() 在 Laravel 5.3 中为 null

jdo*_*doe 5 authentication guard laravel laravel-5 laravel-5.3

我正在尝试将当前用户对象传递给所有模板,如下所示:

class Controller extends BaseController
{
    public function __construct()
    {
        view()->share('usr', Auth::guard('user'));
    }
}
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每个控制器都由控制器扩展。但是,如果我尝试转储Auth::guard('user')->user()Laravel 返回 null,尽管我已登录。此外,当我将此变量传递到模板时,{{ $usr->user() }}返回当前用户。我做错了什么?

我的配置/auth.php

'defaults' => [
    'guard' => 'user',
    'passwords' => 'users',
],
'guards' => [
        'user' => [
            'driver' => 'session',
            'provider' => 'user',
        ],
    ],
'providers' => [
        'user' => [
            'driver' => 'eloquent',
            'model' => App\User::class,
        ],
    ],
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内核.php

         protected $middleware = [
     \Illuminate\Foundation\Http\Middleware\CheckForMaintenanceMode::class,
 ];

/**
 * The application's route middleware groups.
 *
 * @var array
 */
protected $middlewareGroups = [
    'web' => [
        \App\Http\Middleware\EncryptCookies::class,
        \Illuminate\Cookie\Middleware\AddQueuedCookiesToResponse::class,
        \Illuminate\Session\Middleware\StartSession::class,
        \Illuminate\View\Middleware\ShareErrorsFromSession::class,
        //\App\Http\Middleware\VerifyCsrfToken::class,
        \Illuminate\Routing\Middleware\SubstituteBindings::class,
    ],

    'api' => [
        'throttle:60,1',
        'bindings',
    ],
];

/**
 * The application's route middleware.
 *
 * These middleware may be assigned to groups or used individually.
 *
 * @var array
 */
protected $routeMiddleware = [
    'auth' => \Illuminate\Auth\Middleware\Authenticate::class,
    'auth.basic' => \Illuminate\Auth\Middleware\AuthenticateWithBasicAuth::class,
    'bindings' => \Illuminate\Routing\Middleware\SubstituteBindings::class,
    'can' => \Illuminate\Auth\Middleware\Authorize::class,
    'guest' => \App\Http\Middleware\RedirectIfAuthenticated::class,
    'throttle' => \Illuminate\Routing\Middleware\ThrottleRequests::class,
];
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我自己的登录功能:

public function authorizes(Request $request)
{
        $this->validate($request, [
        'login' => 'required|max:50',
        'password' => 'required|max:50'
    ]);

        $credentials = $request->only(['login', 'password' ]);
        $remember = $request->get('remember', false) == 1 ? true : false;

    if ($this->guard->attempt( $credentials, $remember)) {
        $user = $this->guard->user();
        $user->last_login = date('Y-m-d H:i:s');
        $user->save();
        return redirect()->route( 'homepage' )->withSuccess(trans('app.login.success'));
    }
    return redirect()->back()->withErrors(trans('app.wrong.credentials'));
}
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Mar*_*łek 3

在 Laravel 5.3 中,您应该像这样更改控制器构造函数以使其工作(假设您至少使用 Laravel 5.3.4):

public function __construct()
{
    $this->middleware(function ($request, $next) {
        view()->share('usr', Auth::guard('user'));

        return $next($request);
    });
}
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您可以在升级指南中看到此更改的描述:

在 Laravel 的早期版本中,您可以在控制器的构造函数中访问会话变量或经过身份验证的用户。这从来就不是该框架的一个明确功能。在 Laravel 5.3 中,您无法在控制器的构造函数中访问会话或经过身份验证的用户,因为中间件尚未运行。

作为替代方案,您可以直接在控制器的构造函数中定义基于闭包的中间件。在使用此功能之前,请确保您的应用程序正在运行 Laravel 5.3.4