"as.X"运算符通常将一种类型转换为另一种类型,但as.integer在应用于数组时失败.这是一个错误吗?这是Microsoft R Open版本3.3 64位,也是R Foundation的R 3.3.1 for i686-pc-cygwin(32位).
> m <- matrix(rnorm(25), 5)
> m
[,1] [,2] [,3] [,4] [,5]
[1,] -0.5958330 -0.3139274 -0.4746246 0.2431716 -0.5245235
[2,] 0.5677058 0.1944457 -2.3786936 0.2516587 -0.3541963
[3,] 0.6763564 -1.7285476 -0.5878008 -1.2277048 0.7737145
[4,] -1.4607755 -0.4761012 1.0995414 0.6978072 0.6120277
[5,] 0.8593707 0.2962030 1.1791963 -0.2276658 1.1559314
> m[] <- as.integer(m)
> m
[,1] [,2] [,3] [,4] [,5]
[1,] 0 0 0 0 0
[2,] 0 0 -2 0 0
[3,] 0 -1 0 -1 0
[4,] -1 0 1 0 0
[5,] 0 0 1 0 1
> m[] <- as.character(m)
> m
[,1] [,2] [,3] [,4] [,5]
[1,] "0" "0" "0" "0" "0"
[2,] "0" "0" "-2" "0" "0"
[3,] "0" "-1" "0" "-1" "0"
[4,] "-1" "0" "1" "0" "0"
[5,] "0" "0" "1" "0" "1"
> m[] <- as.integer(m)
> m
[,1] [,2] [,3] [,4] [,5]
[1,] "0" "0" "0" "0" "0"
[2,] "0" "0" "-2" "0" "0"
[3,] "0" "-1" "0" "-1" "0"
[4,] "-1" "0" "1" "0" "0"
[5,] "0" "0" "1" "0" "1"
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文件说明:
当索引表达式出现在赋值的左侧(称为子分配)时,x的该部分将设置为赋值右侧的值.在这种情况下,不进行字符索引的部分匹配,并且根据需要强制左侧接受值.对于向量,答案将是层次结构raw <logical <integer <double <complex <character <list <expression中x和类型中较高的类型.
您在左侧看到的子分配行为与记录的行为一致.
请注意,即使as.integer直接应用于双矩阵在这种情况下"有效",它仍然遵循类型层次结构并且仅循环:
> m <- matrix(rnorm(25), 5)
> str(m)
num [1:5, 1:5] 1.3807 -0.0858 1.4478 0.9509 0.6397 ...
> typeof(m)
[1] "double"
> m[] <- as.integer(m)
> str(m)
num [1:5, 1:5] 1 0 1 0 0 0 0 0 -1 -1 ...
> typeof(m)
[1] "double"
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最后,as.integer通常不会将字符转换为有效整数:
> str(as.integer("a"))
int NA
Warning message:
In str(as.integer("a")) : NAs introduced by coercion
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...除了它导致整数味道NA,即NA_integer_.但只要没有子分配,它就会将字符转换为整数:
> str(as.integer("1"))
int 1
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为了解决关于向量的注释,记录的行为在常规向量上是相同的:
> x <- rnorm(5)
> x[] <- as.character(x)
> x
[1] "0.687551073804054" "-1.17843752343875" "0.144747745284427" "-0.931480738737143" "0.394279275668583"
> x[] <- as.integer(x)
> x
[1] "0" "-1" "0" "0" "0"
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