我有一个输入:
results = [
[ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS1", "small", "SW192EZ", "undefined" ],
[ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined" ],
[ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined" ],
[ "Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "medium", "SW192EZ", "undefined" ],
]
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我希望输出类似于
small
DryKISS1 : 1
medium
DryKISS2 : 1
large
DryKISS1 : 5
DryKISS2 : 2
DryKISS3 : 1
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基本上按大小分组,然后在相同大小的括号中汇总公司名称。
我一直在玩下面的游戏,但是因为大多数示例都是针对哈希/对象的,所以我迷路了
console.log _.chain( results ).groupBy( 4 ).map( ( value, key ) ->
[
key
_.reduce( value, ( ( result, currentObject ) ->
{
company: result[ 3 ]
}
))
]
).value()
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按第 4 列分组,然后使用变换按第 3 列计算项目:
var data = [
["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS1", "small", "SW192EZ", "undefined"],
["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"],
["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "large", "SW192EZ", "undefined"],
["Mon Nov 14 08:08:14 GMT+07:00 2016", "Ian Warner", "ian.warner@drykiss.com", "DryKISS2", "medium", "SW192EZ", "undefined"],
];
var result = _(data)
.groupBy(4)
.transform(function(result, items, key) {
result[key] = _.countBy(items, 3);
})
.value();
console.log(result);Run Code Online (Sandbox Code Playgroud)
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