如何将 applicationContext.xml 中的对象转换为 java 注释

E2r*_*abi 5 java spring spring-mvc entitymanager spring-data-jpa

我正在开发一个 spring mvc 项目,我想转换我在我在 spring mvc 3 上工作时编写的 applicationContext.xml 中的 jpa 配置,现在我想转移到 spring Mvc 4 并编写我所有的 Jpa仅使用 Java 注释的配置有人可以帮助我

这是我的 applicationContext 文件:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd">


 <bean id="datasource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
  <property name="driverClassName" value="com.mysql.jdbc.Driver"></property>
  <property name="url" value="jdbc:mysql://localhost:3306/db_adpub"></property>
  <property name="username" value="root"></property>
  <property name="password" value=""></property>
  </bean>

<bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
<property name="persistenceXmlLocations">
 <list>
    <value>classpath*:META-INF/persistence.xml</value>
  </list>
</property>
<property name="defaultDataSource" ref="datasource"></property>
</bean>

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
   <property name="persistenceUnitManager" ref="persistenceUnitManager"></property>
   <property name="persistenceUnitName" value="adpub"></property>
</bean>

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
  <property name="entityManagerFactory" ref="entityManagerFactory"></property>
</bean>

<tx:annotation-driven transaction-manager="transactionManager" />
<context:annotation-config></context:annotation-config>
<mvc:annotation-driven />
</beans>
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慈悲为怀

Kay*_*ayV 2

您必须创建 spring bean 组件(或 beans),如下所示:

@Compnonent
MyTransactionManager
{
@Autowired
EntityManagerFactory entityManagerFactory;

...Constructor to set properties and entityManagerFactory
...Getters and setters

}

@Component
entityManagerFactory{
persistenceUnitName

@Autowired
PersistenceUnitManager persistenceUnitManager

...Constructor to set properties and persistenceUnitManager
...Getters and setters
}

@Component
persistenceUnitManager{
Values as described in properties file, for example like

public @Value("${version}") String version;

...Constructor to set properties 
...Getters and setters

}
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