TypeError:translate()只接受一个参数(给定2个)

pK.*_*pK. 2 python string python-2.7 python-3.x

我的代码在python 2.x版本上运行正常但是当我试图在python 3.x版本上运行它时,它给出了错误.

subject:需要缩写sms编码中的任何消息.

码:

def sms_encoding(data):
    #start writing your code here
    print(data)
    data.split(" ")
    data_list=data.split(" ")
    sms_encd=[]
    final_sms=""
    for i in range(len(data_list)):
        if data_list[i].lower() in  ['a','e','i','o','u']:
            sms_encd.append(data_list[i])
        elif len(data_list[i])>1:
            a = data_list[i].translate(None,'aeiouAEIOU')
            sms_encd.append(a)
    for j in range(len(sms_encd)):
        final_sms += str(sms_encd[j])+" "
    return final_sms[:-1]
data="I will not repeat mistakes"
print(sms_encoding(data)) 
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输出:

2.x版本:

I will not repeat mistakes
I wll nt rpt mstks
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3.x版本:

I will not repeat mistakes
Traceback (most recent call last):
  File "python", line 18, in <module>
  File "python", line 12, in sms_encoding
TypeError: translate() takes exactly one argument (2 given)
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为什么translate()不工作?还有其他替代方法吗?

Mar*_*ers 6

您需要将Python 3 str.translate()与Python 2 进行比较unicode.translate().两者都采用从代码点(整数)到替换(另一个整数或单字符Unicode e字符串)的映射.

str类型有一个静态方法str.maketrans(),它将字符到删除(Python 2的第二个参数str.translate())作为第三个参数,来生成这样的映射.在这里使用:

map = str.maketrans('', '', 'aeiouAEIOU')
a = data_list[i].translate(map)
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这会输出一个字典,将每个元音代码点映射到None:

>>> str.maketrans('', '', 'aeiouAEIOU')
{97: None, 101: None, 105: None, 111: None, 117: None, 65: None, 69: None, 73: None, 79: None, 85: None}
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