Tot*_*.js 4 python upload google-app-engine
这是我从flex 4文件引用上传得到的:
self.request =
Request: POST /UPLOAD
Accept: text/*
Cache-Control: no-cache
Connection: Keep-Alive
Content-Length: 51386
Content-Type: multipart/form-data; boundary=----------ei4cH2gL6ae0ei4ae0gL6GI3KM7ei4
Host: localhost:8080
User-Agent: Shockwave Flash
------------ei4cH2gL6ae0ei4ae0gL6GI3KM7ei4
Content-Disposition: form-data; name="Filename"
36823_117825034935819_100001249682611_118718_676534_n.jpg
------------ei4cH2gL6ae0ei4ae0gL6GI3KM7ei4
Content-Disposition: form-data; name="Filedata"; filename="36823_117825034935819_100001249682611_118718_676534_n.jpg"
Content-Type: application/octet-stream
???? [AND OTHER STRANGE CHARACTERS]
我的课:
class Upload(webapp.RequestHandler):
def post(self):
content = self.request.get("Filedata")
return "done!"
现在我在Upload类中缺少什么才能将该文件保存到磁盘？我在内容var中有一些奇怪的字符(在调试中查看).
App Engine应用程序不能:
- 写入文件系统.应用程序必须使用App Engine数据存储区来存储持久数据.
您需要做的是向用户呈现带有文件上载字段的表单.
提交表单时,将上载文件,Blobstore会根据文件的内容创建一个blob,并返回一个blob键,以便稍后检索和提供blob.
允许的最大对象大小为2千兆字节.
这是一个可以尝试的工作代码段:
#!/usr/bin/env python
#
import os
import urllib
from google.appengine.ext import blobstore
from google.appengine.ext import webapp
from google.appengine.ext.webapp import blobstore_handlers
from google.appengine.ext.webapp import template
from google.appengine.ext.webapp.util import run_wsgi_app
class MainHandler(webapp.RequestHandler):
def get(self):
upload_url = blobstore.create_upload_url('/upload')
self.response.out.write('<html><body>')
self.response.out.write('<form action="%s" method="POST" enctype="multipart/form-data">' % upload_url)
self.response.out.write("""Upload File: <input type="file" name="file"><br> <input type="submit"
name="submit" value="Submit"> </form></body></html>""")
class UploadHandler(blobstore_handlers.BlobstoreUploadHandler):
def post(self):
upload_files = self.get_uploads('file')
blob_info = upload_files[0]
self.redirect('/serve/%s' % blob_info.key())
class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler):
def get(self, resource):
resource = str(urllib.unquote(resource))
blob_info = blobstore.BlobInfo.get(resource)
self.send_blob(blob_info)
def main():
application = webapp.WSGIApplication(
[('/', MainHandler),
('/upload', UploadHandler),
('/serve/([^/]+)?', ServeHandler),
], debug=True)
run_wsgi_app(application)
if __name__ == '__main__':
main()
EDIT1:
在您的特定情况下,您可以使用BlobProperty(限制为1MB)来存储您的请求:
class Photo(db.Model):
imageblob = db.BlobProperty()
然后调整您webapp.RequestHandler的保存您的请求:
class Upload(webapp.RequestHandler):
def post(self):
image = self.request.get("Filedata")
photo = Photo()
photo.imageblob = db.Blob(image)
photo.put()
编辑2:
您不需要更改您的app.yaml,只需添加一个新的处理程序并将其映射到您的WSGI中.要检索存储的照片,您应该添加另一个处理程序来为照片提供服务:
class DownloadImage(webapp.RequestHandler):
def get(self):
photo= db.get(self.request.get("photo_id"))
if photo:
self.response.headers['Content-Type'] = "image/jpeg"
self.response.out.write(photo.imageblob)
else:
self.response.out.write("Image not available")
然后映射你的新DownloadImage类:
application = webapp.WSGIApplication([
...
('/i', DownloadImage),
...
], debug=True)
您可以使用以下网址获取图片:
yourapp/i?photo_id = photo_key
根据要求,如果由于任何奇怪的原因你真的想用这种网址提供你的图像www.mysite.com/i/photo_key.jpg,你可能想尝试这个:
class Download(webapp.RequestHandler):
def get(self, photo_id):
photo= db.get(db.Key(photo_id))
if photo:
self.response.headers['Content-Type'] = "image/jpeg"
self.response.out.write(photo.imageblob)
else:
self.response.out.write("Image not available")
略有不同的映射:
application = webapp.WSGIApplication([
...
('/i/(\d+)\.jpg', DownloadImage),
...
], debug=True)
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