如何在laravel中使用GROUP_CONCAT

Dip*_*kar 15 laravel laravel-5.2

$assignment = assignment::find(Crypt::decrypt($id));
$assignment_details = $assignment->raw_plan()->groupBy('flag')->get();
Run Code Online (Sandbox Code Playgroud)

我想在laravel中关注此查询的结果

SELECT GROUP_CONCAT(name) AS 'names' FROM `raw_plans` where `assignment_id` = 1 GROUP BY`flag`
Run Code Online (Sandbox Code Playgroud)

请建议我如何在laravel中使用GROUP_CONCAT

Ami*_*pta 20

您可以使用关系作为查询构建器来获取结果:

$assignment_details = $assignment->raw_plan()
                                ->select(DB::raw('group_concat(name) as names'))
                                ->where('assignment_id', 1)
                                ->groupBy('flag')
                                ->get();
Run Code Online (Sandbox Code Playgroud)

更新

table_name.*在select中使用以获取所有字段.

$assignment_details = $assignment->raw_plan()
                                ->select('raw_plans.*', DB::raw('group_concat(name) as names'))
                                ->where('assignment_id', 1)
                                ->groupBy('flag')
                                ->get();
Run Code Online (Sandbox Code Playgroud)


Sau*_*ogi 7

shoieb有些正确,但你应该在访问列名之前给出表名 DB:raw()

你应该试试这个:

$data = DB::table('raw_plans')
            ->select(DB::raw("group_concat(raw_plans.name)"))
            ->groupBy('flag')
            ->where('assignement_id',1)
            ->get();
Run Code Online (Sandbox Code Playgroud)

希望这可以帮助.


sho*_*101 5

尝试以下代码

$data = DB::table('raw_plans')
            ->select(DB::raw("GROUP_CONCAT(name SEPARATOR '-') as `names`"))
            ->groupBy('flag')
           ->where('assignement_id',1)
            ->get();
Run Code Online (Sandbox Code Playgroud)