Jos*_*ill 8 javascript reactjs react-native
我在将数据发布到我fetch在react-native应用程序中使用的快速REST API时遇到了问题.这是我的代码:
/**
* Sample React Native App
* https://github.com/facebook/react-native
* @flow
*/
import React, { Component } from 'react';
import {
AppRegistry,
StyleSheet,
Text,
View
} from 'react-native';
import Button from 'react-native-button';
import DeviceInfo from 'react-native-device-info'
export default class ReliefMobile extends Component {
state: any;
constructor(props) {
super(props);
this.state = {
currentLocation: {latitude: 40.6391, longitude: 10.9969},
name: 'Some dumb name',
description: 'Some dumb description',
deviceId: DeviceInfo.getUniqueID()
}
}
addData() {
fetch('http://localhost:3000/api/effort/add', {
method: 'POST',
headers: {
'Accept': 'application/json',
'Content-Type': 'application/json',
},
body: JSON.stringify({
name: this.state.name,
description: this.state.description,
deviceId: this.state.deviceId,
currentLocation: this.state.currentLocation
})
});
}
render() {
return (
<View style={styles.container}>
<Text style={styles.welcome}>
Welcome to React Native
</Text>
<Text style={styles.instructions}>
Your device ID is {DeviceInfo.getUniqueID()}
</Text>
<Text style={styles.instructions}>
Effort Name: {this.state.name}
</Text>
<Text style={styles.instructions}>
Effort Description: {this.state.description}
</Text>
<Text style={styles.instructions}>
Location: {this.state.currentLocation.latitude}, {this.state.currentLocation.longitude}
</Text>
<Button onPress={this.addData}>Add data</Button>
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
justifyContent: 'center',
alignItems: 'center',
backgroundColor: '#F5FCFF',
},
welcome: {
fontSize: 20,
textAlign: 'center',
margin: 10,
},
instructions: {
textAlign: 'center',
color: '#333333',
marginBottom: 5,
},
});
AppRegistry.registerComponent('ReliefMobile', () => ReliefMobile);
Run Code Online (Sandbox Code Playgroud)
当我尝试按下我的按钮来调用该addData函数时,我收到此错误:undefined is not an object (evaluating this.state.name).
在加载应用程序时,我的状态变量似乎正好加载到这些<Text/>区域:

但是,当我提交时,这是显示:

当我改变的身体fetch是一样的东西
body: JSON.stringify({name: 'some name', description: 'some description'})
Run Code Online (Sandbox Code Playgroud)
它工作正常.所以我认为函数this内部的值可能不一样fetch,所以在addData()我的顶部做了类似的事情let that = this;并设置了我的所有状态变量,that.state.name, etc但仍然没有用.
React处理程序不会自动绑定到它们所在的元素/类.
<Button onPress={this.addData.bind(this)}>Add data</Button>
Run Code Online (Sandbox Code Playgroud)
https://facebook.github.io/react/docs/handling-events.html
摘自上面的链接
// This syntax ensures `this` is bound within handleClick
return (
<button onClick={(e) => this.handleClick(e)}>
Click me
</button>
);
Run Code Online (Sandbox Code Playgroud)
您应该在构造函数中绑定而不是在渲染函数中。在您的构造函数中,只需添加:
this.addData = this.addDate.bind(this);
您还可以使用 ES6 作为另一种选择:
addData = () => { ... }
这将按照此处记录的方式工作:https : //babeljs.io/blog/2015/06/07/react-on-es6-plus在箭头功能部分下。