And*_*urn 4 mysql datetime mariadb
所以我有一个看起来像这样的插入:
INSERT INTO TempDupeData (Sys_InvoiceID, DupeSetID, Netted, InvoiceNo, InvoiceDate, Sys_SupplierID, SuppInvNo, NetAmount, VATAmount, GrossAmount, PayDate, PayRef,PayRefNo, PayType,
PayAmount, Curr, GBPNetAmount, GBPVATAmount, GBPGrossAmount, NetAmountAbs, GrossAmountAbs, VATAmountAbs, DocType, SuppInvNoNums, VATPerc, VATA, VATB, VATC,
VATD, VATE, VATPotentialClaim, ClaimStatus, SuppInvNoSubst, SuppInvNoSubstFlag, DupeSubstGross, DupeSubstNet, SuppInvNoCharMap, SuppInvNoCharMapFlag, SeqErrFlag)
SELECT
FK_SysInvoiceID,
CONCAT(CTE.NetAmountAbs, CTE.AccountNumber),
Netted,
InvoiceNo,
InvoiceDate,
I.FK_SupplierID,
SuppInvNo,
NetAmount,
VATAmount,
GrossAmount,
PayDate,
PayRef,
PayRefNo,
PayType,
PayAmount,
Curr,
GBPNetAmount,
GBPVATAmount,
GBPGrossAmount,
CTE.NetAmountAbs,
GrossAmountAbs,
VATAmountAbs,
DocType,
SuppInvNoNums,
VATPerc,
VATA,
VATB,
VATC,
VATD,
VATE,
VATPotentialClaim,
ClaimStatus,
SuppInvNoSubst,
SuppInvNoSubstFlag,
DupeSubstGrs,
DupeSubstNet,
SuppInvNoCharMap,
SuppInvNoCharMapFlag,
SeqErrFlag
FROM (SELECT
FK_SupplierID,
AccountNumber,
NetAmountAbs,
CASE WHEN MIN(NetAmountAbs) < SUM(NetAmount) THEN 0 ELSE -1 END AS Netted
FROM invoice
WHERE NetAmountAbs >= 500 and InvoiceDate IS NOT null
GROUP BY FK_SupplierID,
NetAmountAbs
HAVING COUNT(*) > 1
AND ((SUM(CASE WHEN NetAmount >= 0 THEN 1 ELSE 0 END)) > 1)
AND (MAX(SuppInvNoNums) != MIN(SuppInvNoNums))
AND (MIN(InvoiceDate) != MAX(InvoiceDate))
AND (DATE_SUB(MAX(COALESCE(InvoiceDate, NOW())) <= MIN(COALESCE(InvoiceDate, NOW())), INTERVAL 30 DAY))
AND (MAX(GrossAmountAbs) != MIN(GrossAmountAbs))) CTE
INNER JOIN invoice I
ON CTE.NetAmountAbs = I.NetAmountAbs
AND CTE.FK_SupplierID = I.FK_SupplierID
ORDER BY CTE.NetAmountAbs DESC, CTE.FK_SupplierID;
Run Code Online (Sandbox Code Playgroud)
它从表中执行,执行一些计算,连接自身然后插入.它失败了这条消息:Incorrect DateTime Value '0000-00-00 00:00:00'.我缩小了它,如果我从having子句中删除这一行(DATE_ADD(MAX(COALESCE(InvoiceDate, NOW())) <= MIN(COALESCE(InvoiceDate, NOW())), INTERVAL -30 DAY))就可以了.
事实上,当我奇怪地删除插入时,它可以工作.
选择不会返回任何内容但它仍然失败.
为什么是这样?任何人都可以帮忙找出原因吗?
kra*_*kov 15
第一种选择:
这个警告可能是由于SQL_MODE.
根据mysql文档"如果启用了NO_ZERO_DATE或NO_ZERO_IN_DATE SQL模式,则不允许零日期或部分日期." 所以这可能是你INSERT的'0000-00-00 00:00:00'失败的原因.
您可以通过执行以下命令来检查您的sql模式:
SELECT @@sql_mode;
Run Code Online (Sandbox Code Playgroud)
如果有任何NO_ZERO_DATE或NO_ZERO_IN_DATE设置,那么你可以:
SET sql_mode = '';
Run Code Online (Sandbox Code Playgroud)
第二种选择
另一种选择是由于STRICT_TRANS_TABLES模式而失败.正如mysql文档所说:
严格模式会影响服务器是否允许'0000-00-00'作为有效日期:如果未启用严格模式,则允许使用'0000-00-00'并且插入不会产生警告.如果启用了严格模式,则不允许使用'0000-00-00',并且插入会产生错误,除非同时给出了IGNORE.对于INSERT IGNORE和UPDATE IGNORE,允许使用'0000-00-00'并且插入产生警告
这对于datetime也是有效的.
因此,您必须禁用STRICT MODE 或禁用它不是一个选项 - 修改查询,使其不返回无效的日期/日期时间结果