Ruby中多个哈希的摘要

Arc*_*her 1 ruby hash sum ruby-on-rails

通过选择,我得到以下回应:

=> [{:month=>[3, 3, 9, 14, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
:dates=>["30.10:", "29.10:", "28.10:", "27.10:", "26.10:", "25.10:", "24.10:", "23.10:", "22.10:", "21.10:", "20.10:", "19.10:", "18.10:", "17.10:", "16.10:", "15.10:", "14.10:", "13.10:", "12.10:", "11.10:", "10.10:", "09.10:", "08.10:", "07.10:", "06.10:", "05.10:", "04.10:", "03.10:", "02.10:", "01.10:"]},
{:month=>[1, 3, 5, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
:dates=>["30.10:", "29.10:", "28.10:", "27.10:", "26.10:", "25.10:", "24.10:", "23.10:", "22.10:", "21.10:", "20.10:", "19.10:", "18.10:", "17.10:", "16.10:", "15.10:", "14.10:", "13.10:", "12.10:", "11.10:", "10.10:", "09.10:", "08.10:", "07.10:", "06.10:", "05.10:", "04.10:", "03.10:", "02.10:", "01.10:"]}]
Run Code Online (Sandbox Code Playgroud)

在此示例中,有两组哈希值.可能会有更多结果,但每次的日期都是相同的.

有没有一种简单的方法将它与以下结果相结合?

[{:month=>[4, 6, 14, 16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
:dates=>["30.10:", "29.10:", "28.10:", "27.10:", "26.10:", "25.10:", "24.10:", "23.10:", "22.10:", "21.10:", "20.10:", "19.10:", "18.10:", "17.10:", "16.10:", "15.10:", "14.10:", "13.10:", "12.10:", "11.10:", "10.10:", "09.10:", "08.10:", "07.10:", "06.10:", "05.10:", "04.10:", "03.10:", "02.10:", "01.10:"]}
Run Code Online (Sandbox Code Playgroud)

对于Arrays,我可以使用transpose.map {|x| x.reduce(:+)}但不能用于哈希.哈希有类似的解决方案吗?

Car*_*and 5

arr = [{ :month=>[3, 3, 9], :dates=>["30.10:", "29.10:"] },
       { :month=>[1, 3, 5], :dates=>["30.10:", "29.10:"] },
       { :month=>[2, 4, 6], :dates=>["30.10:", "29.10:"] }]

{ :month=>arr.map { |h| h[:month] }.transpose.map { |a| a.reduce(:+) },
  :dates=>arr.first[:dates] }
  #=> {:month=>[6, 10, 20], :dates=>["30.10:", "29.10:"]} 
Run Code Online (Sandbox Code Playgroud)

步骤如下.

a = arr.map { |h| h[:month] }
  #=> [[3, 3, 9], [1, 3, 5], [2, 4, 6]] 
b = a.transpose
  #=> [[3, 1, 2], [3, 3, 4], [9, 5, 6]] 
c = b.map { |a| a.reduce(:+) }
  #=> [6, 10, 20] 
d = arr.first
  #=> {:month=>[3, 3, 9], :dates=>["30.10:", "29.10:"]} 
e = d[:dates]
  #=> ["30.10:", "29.10:"] 
{ :month=>c, :dates=>e }
  #=> {:month=>[6, 10, 20], :dates=>["30.10:", "29.10:"]} 
Run Code Online (Sandbox Code Playgroud)