使用 Pygame 创建矩形按钮

Question

我正在尝试rect在 Pygame 中使用按钮。我从红色的退出按钮开始，并检查点击是否在按钮的边界框内。

    import pygame
"""import nemesis.py;"""

pygame.init();
screen = pygame.display.set_mode((400,300));
pygame.display.set_caption("menu");
menuAtivo = True;

start_button = pygame.draw.rect(screen,(0,0,240),(150,90,100,50));
continue_button = pygame.draw.rect(screen,(0,244,0),(150,160,100,50));
quit_button = pygame.draw.rect(screen,(244,0,0),(150,230,100,50));


pygame.display.flip();


while menuAtivo:
    for evento in pygame.event.get():
        print(evento);
        if evento.type == pygame.MOUSEBUTTONDOWN:
            if pygame.mouse.get_pos() >= (150,230):
                if pygame.mouse.get_pos() <= (250,280):
                        pygame.quit();
                    

Answer 1

When using rects in pygame, it's best to use the in built collision detection. here is an example code on how to do it hope it helps you solve your problem.

Before that though i'd like to mention you should render/draw your objects withing the while loop or the wont show up.

import pygame
import sys


def main():
    pygame.init()
    clock = pygame.time.Clock()
    fps = 60
    size = [200, 200]
    bg = [255, 255, 255]

    screen = pygame.display.set_mode(size)

    button = pygame.Rect(100, 100, 50, 50)  # creates a rect object
    # The rect method is similar to a list but with a few added perks
    # for example if you want the position of the button you can simpy type
    # button.x or button.y or if you want size you can type button.width or
    # height. you can also get the top, left, right and bottom of an object
    # with button.right, left, top, and bottom

    while True:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                return False

            if event.type == pygame.MOUSEBUTTONDOWN:
                mouse_pos = event.pos  # gets mouse position

                # checks if mouse position is over the button

                if button.collidepoint(mouse_pos):
                    # prints current location of mouse
                    print('button was pressed at {0}'.format(mouse_pos))

        screen.fill(bg)

        pygame.draw.rect(screen, [255, 0, 0], button)  # draw button

        pygame.display.update()
        clock.tick(fps)

    pygame.quit()
    sys.exit


if __name__ == '__main__':
    main()

Answer 2

TKS 伙计们，

这是我的回答：

import pygame


pygame.init();
screen = pygame.display.set_mode((400,300));
pygame.display.set_caption("menu");
menuAtivo = True;

start_button = pygame.draw.rect(screen,(0,0,240),(150,90,100,50));
continue_button = pygame.draw.rect(screen,(0,244,0),(150,160,100,50));
quit_button = pygame.draw.rect(screen,(244,0,0),(150,230,100,50));


pygame.display.flip();

def startGame():
    screen.fill((0,0,0));
    pygame.display.flip();
    import nemesis.py;

while menuAtivo:
    for evento in pygame.event.get():
        print(evento);
        if evento.type == pygame.MOUSEBUTTONDOWN:
            if pygame.mouse.get_pos()[0] >= 150 and pygame.mouse.get_pos()[1] >= 230:
                if pygame.mouse.get_pos()[0] <= 250 and pygame.mouse.get_pos()[1] <= 280:
                        pygame.quit();
            if pygame.mouse.get_pos()[0] >= 150 and pygame.mouse.get_pos()[1] >= 90:
                if pygame.mouse.get_pos()[0] <= 250 and pygame.mouse.get_pos()[1] <= 140:
                        startGame();