pyt*_*nic 1 scala kryo apache-spark
我有以下代码:
val conf = new SparkConf().setAppName("MyApp")
val sc = new SparkContext(conf)
conf.set("spark.serializer", "org.apache.spark.serializer.KryoSerializer")
new conf.registerKryoClasses(new Class<?>[]{
Class.forName("org.apache.hadoop.io.LongWritable"),
Class.forName("org.apache.hadoop.io.Text")
});
Run Code Online (Sandbox Code Playgroud)
但我碰到了以下错误:
')' expected but '[' found.
[error] new conf.registerKryoClasses(new Class<?>[]{
Run Code Online (Sandbox Code Playgroud)
我怎么解决这个问题 ?
你正在混合使用Scala和Java.在Scala中,您可以定义Array[Class[_]](而不是a Class<?>[]):
val conf = new SparkConf()
.setAppName("MyApp")
.set("spark.serializer", "org.apache.spark.serializer.KryoSerializer")
.registerKryoClasses(Array[Class[_]](
Class.forName("org.apache.hadoop.io.LongWritable"),
Class.forName("org.apache.hadoop.io.Text")
));
val sc = new SparkContext(conf)
Run Code Online (Sandbox Code Playgroud)
我们甚至可以做得更好.为了不使用字符串文字使我们的类错误,我们实际上可以利用这些类并使用classOf它们来获取它们的类类型:
import org.apache.hadoop.io.LongWritable
import org.apache.hadoop.io.Text
val conf = new SparkConf()
.setAppName("MyApp")
.set("spark.serializer", "org.apache.spark.serializer.KryoSerializer")
.registerKryoClasses(Array[Class[_]](
classOf[LongWritable],
classOf[Test],
))
val sc = new SparkContext(conf)
Run Code Online (Sandbox Code Playgroud)